tf.shape() 在张量流中得到错误的形状 [英] tf.shape() get wrong shape in tensorflow
问题描述
我定义一个这样的张量:
I define a tensor like this:
x = tf.get_variable("x", [100])
但是当我尝试打印张量的形状时:
But when I try to print shape of tensor :
print(tf.shape(x))
我得到Tensor("Shape:0", shape=(1,), dtype=int32),为什么输出的结果不应该是shape=(100)
I get Tensor("Shape:0", shape=(1,), dtype=int32), why the result of output should not be shape=(100)
推荐答案
tf.shape(input, name=None) 返回表示输入形状的一维整数张量.
tf.shape(input, name=None) returns a 1-D integer tensor representing the shape of input.
您正在寻找: x.get_shape()
返回 x
变量的 TensorShape
.
You're looking for: x.get_shape()
that returns the TensorShape
of the x
variable.
更新:由于这个答案,我写了一篇文章来阐明 Tensorflow 中的动态/静态形状:https://pgaleone.eu/tensorflow/2018/07/28/understanding-tensorflow-tensors-shape-static-dynamic/
Update: I wrote an article to clarify the dynamic/static shapes in Tensorflow because of this answer: https://pgaleone.eu/tensorflow/2018/07/28/understanding-tensorflow-tensors-shape-static-dynamic/
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