使用python regex从字符串中单独提取子字符串 [英] Extract substrings separately from a string using python regex

问题描述

我正在尝试编写一个正则表达式，它返回字符串后面的子字符串的一部分.例如:我想获取子字符串的一部分以及位于15/08/2017"之后的空格.

I am trying to write a regular expression which returns a part of substring which is after a string. For example: I want to get part of substring along with spaces which resides after "15/08/2017".

a='''S
LINC             SHORT LEGAL                                   TITLE NUMBER
0037 471 661     1720278;16;21                                 172 211 342

LEGAL DESCRIPTION
PLAN 1720278  
BLOCK 16  
LOT 21  
EXCEPTING THEREOUT ALL MINES AND MINERALS  

ESTATE: FEE SIMPLE  
ATS REFERENCE: 4;24;54;2;SW

MUNICIPALITY: CITY OF EDMONTON

REFERENCE NUMBER: 172 023 641 +71

---------------------------------------------------------------------------- 
----
             REGISTERED OWNER(S)
REGISTRATION    DATE(DMY)  DOCUMENT TYPE      VALUE           CONSIDERATION
--------------------------------------------------------------------------- 
-- 
---

172 211 342    15/08/2017  AFFIDAVIT OF                       CASH & MTGE'''

有没有办法获得 'AFFIDAVIT OF' 和 'CASH &MTGE' 作为单独的字符串?

Is there a way to get 'AFFIDAVIT OF' and 'CASH & MTGE' as separate strings?

这是我目前拼凑的表达方式:

Here is the expression I have pieced together so far:

doc = (a.split('15/08/2017', 1)[1]).strip()
'AFFIDAVIT OF                       CASH & MTGE'

推荐答案

不是基于正则表达式的解决方案.但有诀窍.

Not a regex based solution. But does the trick.

a='''S
LINC             SHORT LEGAL                                   TITLE NUMBER
0037 471 661     1720278;16;21                                 172 211 342

LEGAL DESCRIPTION
PLAN 1720278  
BLOCK 16  
LOT 21  
EXCEPTING THEREOUT ALL MINES AND MINERALS  

ESTATE: FEE SIMPLE  
ATS REFERENCE: 4;24;54;2;SW

MUNICIPALITY: CITY OF EDMONTON

REFERENCE NUMBER: 172 023 641 +71

---------------------------------------------------------------------------- 
----
            REGISTERED OWNER(S)
REGISTRATION    DATE(DMY)  DOCUMENT TYPE      VALUE           CONSIDERATION
--------------------------------------------------------------------------- 
-- 
---

172 211 342    15/08/2017  AFFIDAVIT OF                       CASH & MTGE'''

doc = (a.split('15/08/2017', 1)[1]).strip() 
# used split with two white spaces instead of one to get the desired result
print(doc.split("  ")[0].strip()) # outputs AFFIDAVIT OF
print(doc.split("  ")[-1].strip()) # outputs CASH & MTGE

希望有帮助.

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