如何子类化构建命令? [英] How do I subclass the build command?

问题描述

主题是不言自明的:我需要对 setup.py build 命令进行子类化以执行额外的构建步骤.但是我没有找到任何要继承的 build 命令类.我一直在努力:

The subject is self-descriptive: I need to subclass the setup.py build command in order to perform additional build steps. However I've failed to find any build command class to inherit from. I've been trying:

class BuildCommandProxy(setuptools.command.build):
    pass

和

class BuildCommandProxy(distutils.command.build):
    pass

甚至:

class BuildCommandProxy(setuptools.distutils.command.build):
    pass

没有任何成功.

更新:寻找如何使用setuptools<实现this之类的东西/代码>.

UPDATE: looking for how to implement something like this with setuptools.

UPDATE2:我有一些自定义命令实现:

UPDATE2: I have some custom command implementation:

class CustomCommand(setuptools.Command):
    # ...

我想要实现的是将这个命令传递给 cmdclass 像这样:

What I would like to implement is to pass this command to cmdclass like this:

cmdclass={
    "build": CustomCommand,
}

然后在执行一些自定义步骤后调用 CustomCommand.run 中的原始 build.

and then invoke the original build in CustomCommand.run after doing some custom steps.

推荐答案

Setuptools 不会覆盖 distutils build 命令本身；只有 build_py 和 build_ext 子命令.

Setuptools does not override the distutils build command itself; only the build_py and build_ext subcommands.

因此，要创建自己的子类，您需要从 distutils.command.build module 导入，其中包含一个 build 类(Command) 的子类:

So, to create your own subclass you need to import from the distutils.command.build module, which contains a build class (subclass of Command):

import distutils.command.build

class BuildCommandProxy(distutils.command.build.build):
    pass

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