列表中元组的交集 - python [英] intersection of tuples in a list - python

问题描述

我有一个像这样的元组列表:

I have a list of tuples like this :

all_tuples=[(92, 242),(355, 403),(355, 436),(355, 489),(403, 436),(436, 489),(515, 517),(517, 859),(634, 775),(701, 859),(775, 859)]

我需要取所有元组的交集并将它们联合起来.

and I need to take the intersection of all tuples and union them.

The desired result = [{92, 242},{355, 403,436,489},{515, 517,859,701,775,634}]

即相交的元组迭代地联合.

That is the intersected tuples are union iteratively.

我尝试将元组转换为集合，然后求交集，但没有奏效.任何想法?

I tried to convert the tuples to sets and then take the intersection but did not work. Any idea?

推荐答案

这是网络问题，使用networkx

import networkx as nx 
G=nx.Graph()
all_tuples=[(92, 242),(355, 403),(355, 436),(355, 489),(403, 436),(436, 489),(515, 517),(517, 859),(634, 775),(701, 859),(775, 859)]
G.add_edges_from(all_tuples)
list(nx.connected_components(G))
Out[1216]: [{92, 242}, {355, 403, 436, 489}, {515, 517, 634, 701, 775, 859}]

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