单选按钮 - Yii2-Basic-App [英] Radio Button - Yii2-Basic-App

问题描述

在单选按钮中，值来了.但是，我想显示该值的名称.

我的user_types(表格)

id type status created_at1 个人 1 20152 事务所 1 2015

UserController.php(控制器)

公共函数 actionRegister(){$model = 新用户()；..$modelUserType=UserType::find()->select(['id', 'type'])->where(['status' => 1])->indexBy("id")->column();返回 $this->render('注册', ['模型' =>$模型，'modelUserType'=>$modelUserType,'模块' =>$this->模块，]);}

register.php(查看)

<预><代码>..<?=$form->field($model, 'user_type')->radioList($type)->label('你是你吗')?>..

事情是这样的.

我想要这样

所以知道如何显示 'type' 列而不是 'id' 列.

解决方案

Partykar 先生，现在我理解你了.这是我的答案.这对我来说也适用于呈现单选按钮列表.请回复这是解决您的问题

公共函数 actionRegister(){$model = 新用户()；..$modelUserType=UserType::find()->select(['id', 'type'])->where(['status' =>1])->asArray()->all();$type=[];foreach($modelUserType as $k=>$v){if(is_array($v))$type[$v["id"]]=$v["type"];}返回 $this->render('注册', ['模型' =>$模型，'类型'=>$类型，'模块' =>$this->模块，]);}

In radio button, value is coming. But, I want to display the name of that value.

my user_types (table)

id            type              status           created_at
1           An Individual       1                   2015
2           Firm                1                   2015

UserController.php (controller)

public function actionRegister()
{    
    $model = new Users();
    .
    .
    $modelUserType=UserType::find()->select(['id', 'type'])->where(['status' => 1])
                      ->indexBy("id")->column();
    return $this->render('register', [
          'model' => $model,
          'modelUserType'=>$modelUserType,
          'module' => $this->module,
    ]);

}

register.php (view)

.
.
<?=                        
    $form->field($model, 'user_type')
    ->radioList($type)
    ->label('Are You')       
?>
.
.

It's coming like this.

I want like this

So any idea how to bring 'type' column to display instead of 'id' column.

解决方案

Mr Partykar and now i understand you.This is my answer.This is work to me also for render list of radio buttons. Please, reply this is fix your problem

public function actionRegister()
    {    
        $model = new Users();
        .
        .
        $modelUserType=UserType::find()->select(['id', 'type'])->where(['status' => 1])->asArray()->all();
    $type=[];
    foreach($modelUserType as $k=>$v){
                   if(is_array($v))$type[$v["id"]]=$v["type"];

    }

        return $this->render('register', [
              'model' => $model,
              'type'=>$type,
              'module' => $this->module,
        ]);

    }

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