对于数组中的重复值，如何使用“重复"?使用 Ramda.js [英] For duplicate values in an array, how do I use "repeat" with Ramda.js

问题描述

我正在尝试使用 count:[1, 2, 3] 复制 target:[ "a", "b", "c"]

I am trying to duplicate target:[ "a", "b", "c"] with count:[1, 2, 3]

所需的输出是[a"、b"、b"、c"、c"、c"]

它不适用于此代码:

const fn = ({ target, count }) => R.map (R.repeat (target, count))

const Data = { target : ["a", "b", "c"], count : [1, 2, 3] }

const result = fn(Data)

我正在尝试使用 Ramda.js 寻找解决方案.

I am trying to find solution with Ramda.js.

谢谢.

推荐答案

另一个相当简单的解决方案:

Another fairly simple solution:

const fn = ({target, count}) => 
  unnest (zipWith (repeat) (target, count))

const data = {
  target: ['a', 'b', 'c'], 
  count: [1, 2, 3]
}

console .log (fn (data))

<script src="//cdnjs.cloudflare.com/ajax/libs/ramda/0.27.1/ramda.min.js"></script>
<script> const {unnest, zipWith, repeat} = R                             </script>

target 和 data 的无点函数很简单:

A point-free function of target and data is easy enough:

compose (unnest, zipWith (repeat))

如果它们被包裹在一个对象中并且你真的想要无点，那么来自 Hitmands 的答案似乎是最好的，或者使用这种技术的变体:

If they are wrapped in an object and you really want point-free, then the answer from Hitmands seems best, or a variant using this technique:

compose (unnest, apply (zipWith (repeat)), props (['target', 'count']))

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