Stata中R样本函数的等价物是什么 [英] What's the equivalent of R sample function in Stata

问题描述

我有一个关于 Stata 的基本问题.我有 R 编程经验，但我开始了一份新工作，其中 Stata 是主要语言.我目前正在自己​​深入研究 Stata，有时很难理解如何做简单的事情.

I have a basic question about Stata. I have programming experience in R but I've started a new job where Stata is the main language. I'm currently diving into Stata on my own and sometimes it's hard to understand how to do simple things.

我试图获得 3 到 50 之间的 5 个随机数，但没有成功.

I've trying to get 5 random numbers between 3 and 50 but without success.

在 R 中，任何这些都可以工作:

In R, any of these would work:

 floor(runif(5, min=3, max=50))
 16 39 11 11  5 # output

 sample(3:50, 5, replace=TRUE)
 28 13  5 36 19 # output

但我不确定如何在 Stata 中执行此操作，特别是如何返回所需范围(3:50)内的随机数.任何指针将不胜感激.我找到了 runiform() 函数，但我认为我无法获得相同的输出.

But I'm not sure how to do this in Stata, specifically how to return random numbers within the desired range (3:50). Any pointers would be appreciated. I found the runiform() function but I don't think I can get the same output.

推荐答案

这是您想要的吗?

set obs 5
generate rnum = runiform(3, 50)

您基本上是先创建数据集，然后生成具有所需属性的变量.

You are basically creating a dataset first and then generating a variable with the desired properties.

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