有没有办法猜测下一个数字java随机? [英] Is there a way to guess the next number java random?

问题描述

问题在标题中，这里很新，所以对这个网站还不太了解.想使用 hash 来创造更多的随机性"但还不确定 Java 的 Math.Random() 是否有可能破解它?

Question is in the title, quite new here so don't know much about the site yet. Want to use hash for creating "more randomness" but not yet sure about Java's Math.Random() yet, is it possible to crack it?

推荐答案

如果你正在使用 java.util.Random()，这是可能的.看看这个代码

If you are using java.util.Random(), it is possible. Have a look at this Code

为了更好的安全性，你必须使用 SecureRandom 如下

For better security, you have to use SecureRandom as below

SecureRandom secureRandomGenerator = SecureRandom.getInstance("SHA1PRNG");

但最好的解决方案是使用硬件进行随机数生成.

But the best solution, which can't be cracked is using Hardware for Random number generation.

像 MersenneTwister 这样的基于 Random 的算法可以被黑客攻击

Algorithms based on Random like MersenneTwister can be hacked as per this article by Dan Petro

CSPRNGs(密码安全伪随机数生成器)是:

CSPRNGs (Cryptographically secure pseudorandom number generator) to use are:

1. 在类 Unix 系统上从 /dev/urandom 读取

Java SecureRandom 类

.NET RNGCryptoServiceProvider 类

PHP openssl_random_pseudo_bytes() 函数

相比之下，要避免的随机数生成器的一些示例是:

In contrast, some examples of random number generators to avoid are:

1. libc rand() 函数

Java Random 类

The Java Random class

.NET Random 类

The .NET Random class

PHP 的 rand() 和 mt_rand() 函数

PHP’s rand() and mt_rand() functions

看看这篇由 Thomas Huhn 撰写的文章

Have a look at this article by Thomas Huhn

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