返回数组的内存分配，而不是Java值 [英] Array returning memory allocation instead of value in Java

问题描述

考虑一个简单的情况下，像这样的：

Consider a simple case like this one :

public static void array()
{
    String myString = "STACKOVERFLOW";
    int [] checkVal = new int[myString.length()];

    for(int i=0; i<myString.length();i++){
        checkVal[i] = (int)myString.charAt(i);
    }

    System.out.println(checkVal[0]);
    System.out.println(checkVal[1]);
    System.out.println(checkVal[2]);
    System.out.println(checkVal[3]);
    System.out.println(checkVal[4]);
    System.out.println(checkVal);
}

这将输出以下内容：

83
84
65
67
75
[I@fc9944

能否有人请解释这样对我？我怎样才能从数组，而不是它获取正确的信息的内存分配？

Can some one please explain this to me ? How can I retrieve the proper information from the Array instead of it's memory allocation ?

推荐答案

如果您希望它打印$ $ p ptty，使用 Arrays.toString 来做到这一点：

If you want it pretty printed, use Arrays.toString to do it:

System.out.println(Arrays.toString(checkVal);

如果不是，它只是打印出的toString 阵列，这是从对象继承了，和生成的字符串包含它的类型和散列code：

If not, it will just print out the toString of the array, which is inherited from Object, and generated a String contains its type and the hash code:

Object类的toString方法返回一个包含其中的对象是一个实例，该符号字符'@'的类名称的字符串，散列$ C的无符号十六进制再presentation对象$ C。换句话说，该方法返回字符串等于的值：

The toString method for class Object returns a string consisting of the name of the class of which the object is an instance, the at-sign character `@', and the unsigned hexadecimal representation of the hash code of the object. In other words, this method returns a string equal to the value of:

的getClass（）。的getName（）+'@'+ Integer.toHexString（哈希code（））

getClass().getName() + '@' + Integer.toHexString(hashCode())

<一个href=\"http://stackoverflow.com/questions/7060016/why-does-the-tostring-method-in-java-not-seem-to-work\">This答案也有相关的信息。

This answer also has relevant info.

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