检查数字在哪个范围内 [英] Check which range a number is within

问题描述

我需要找出一个数字在哪个范围内，在本例中为 value.除了这个，我找不到任何其他方法来将 i 设置为我需要的:

I need to find which range a number, in this case value, is within. I cannot find any other way to set i to what I need other than this:

if value < -64:
  i = 0
elif value < -32:
  i = 1
elif value < -16:
  i = 2
elif value < -8:
  i = 3
elif value < -4:
  i = 4
elif value < -2:
  i = 5
elif value < -1:
  i = 6
elif value < -0.5:
  i = 7
elif value < 0:
  i = 8
elif value < 0.5:
  i = 9
elif value < 1:
  i = 10
elif value < 2:
  i = 11
elif value < 4:
  i = 12
elif value < 8:
  i = 13
elif value < 16:
  i = 14
elif value < 32:
  i = 15
elif value < 64:
  i = 16
else:
  i = 17

这是糟糕的代码，我讨厌它.有什么办法可以做这样的事情吗?

This is terrible code and I hate it. Is there any way I can do something like this?

ranges = [-64, -32, -16 ... 32, 64]
i = find_which_range(value, ranges)

谢谢！

推荐答案

使用 bisect:

import bisect

ranges = [-64, -32, -16, -8, -4, -2, -1, -0.5, 0, 0.5, 1, 2, 4, 8, 16, 32, 64]

print(bisect.bisect(ranges, -65))
# 0

print(bisect.bisect(ranges, -64))
# 1

print(bisect.bisect(ranges, 63))
#16

print(bisect.bisect(ranges, 64))
# 17

bisect.bisect(l, value) 返回必须在 l 中插入 value 的索引，这样所有的值左边小于 value.搜索大列表也会很快，因为它使用二分算法.

bisect.bisect(l, value) returns the index at which value would have to be inserted in l, such that all values to the left are less than value. It will also be fast to search a large list, as it uses a bisection algorithm.

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