SQL RANK() 在连接表上的 PARTITION [英] SQL RANK() over PARTITION on joined tables

问题描述

我有两个表 RSLTS 和 CONTACTS:

I have two tables RSLTS and CONTACTS:

RSLTS

 QRY_ID  |  RES_ID  |  SCORE
-----------------------------
   A     |    1     |    15
   A     |    2     |    32
   A     |    3     |    29
   C     |    7     |    61
   C     |    9     |    30

联系方式

 C_ID  |  QRY_ID  |  RES_ID
----------------------------
  1    |    A     |    2
  2    |    A     |    1
  3    |    C     |    9

我正在尝试创建一个报告，该报告将为每个 CONTACT 记录 (C_ID) 显示 RANK() 的 RANK()代码>RES_ID(按SCORE)在其组内的RSLTS 表中(QRY_ID).使用上面的数据，它看起来像这样:

I'm trying to create a report that would show, for each CONTACT record (C_ID), the RANK() of RES_ID (by SCORE) in the RSLTS table within its group (QRY_ID). Using the data above, it would look like this:

 C_ID  |  QRY_ID  |  RES_ID  |  SCORE  |  Rank
-----------------------------------------------
  1    |    A     |    2     |    32   |   1
  2    |    A     |    1     |    15   |   3
  3    |    C     |    9     |    30   |   2

到目前为止，我尝试过这个，但它在最后一行返回 Rank = 1(第二行的 rank = 2 这也是错误的)

So far, I tried this but it returns Rank = 1 for the last row (and rank = 2 for the second which is also wrong)

SELECT
    C.*
    ,R.SCORE
    ,RANK() OVER (PARTITION BY R.QRY_ID ORDER BY R.SCORE DESC)
FROM CONTACTS C LEFT JOIN RSLTS R
ON C.RES_ID = R.RES_ID
AND C.QRY_ID = R.QRY_ID

更新:SQLFiddle

推荐答案

因为排名完全不依赖于联系人

As the rank doesn't depend at all from the contacts

RANKED_RSLTS

 QRY_ID  |  RES_ID  |  SCORE |  RANK
-------------------------------------
   A     |    1     |    15  |   3
   A     |    2     |    32  |   1
   A     |    3     |    29  |   2
   C     |    7     |    61  |   1
   C     |    9     |    30  |   2

因此:

SELECT
    C.*
    ,R.SCORE
    ,MYRANK
FROM CONTACTS C LEFT JOIN
(SELECT  *,
 MYRANK = RANK() OVER (PARTITION BY QRY_ID ORDER BY SCORE DESC)
  FROM RSLTS)  R
ON C.RES_ID = R.RES_ID
AND C.QRY_ID = R.QRY_ID

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