Python 中的 Json 到 RDF/XML 文件 [英] Json to RDF/XML file in Python
本文介绍了Python 中的 Json 到 RDF/XML 文件的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我正在尝试保存这个 json 对象:
<预><代码>[{患者 ID":59b70b0e-51cb-4215-b65a-db470067c8de"},[{tel_1_preferred_p":真，"adr_region": "好的","tel_2_number": "800-979-6786","__modelname__": "人口统计","adr_city": "比克斯比",种族":空，"adr_postalcode": "74008","name_family": "约翰",name_middle":空，"tel_1_type": "h","tel_2_type": "c",name_prefix":空，"email": "william.robinson@example.com","name_given": "史密斯","adr_street": "23 Church Rd","生日": "1965-08-09","__documentid__": "65cd1101-b047-4ce5-afc0-778d033229ca","tel_1_number": "800-870-3011","preferred_language": "EN","性别": "男",name_suffix":空，tel_2_preferred_p":真，种族":空，"adr_country": "美国"}],[{"startDate": "2014-10-02T00:00:00Z","name_identifier": "195967001",name_system":空，"notes": "无","name_title": "哮喘","__modelname__": "问题","endDate": "2014-10-13T00:00:00Z","__documentid__": "eaba4e92-3aaf-4d8c-a7db-8cfd563290c6"},{"startDate": "2014-12-02T00:00:00Z","name_identifier": "161155000",name_system":空，"notes": "无","name_title": "学校问题(发现)","__modelname__": "问题","endDate": "2014-12-14T00:00:00Z","__documentid__": "3058b12d-434d-48da-8b14-05dd485946cb"},{"startDate": "2008-07-29T00:00:00Z","name_identifier": "185903001","name_system": "http://purl.bioontology.org/ontology/SNOMEDCT/",注释":空，"name_title": "需要接种流感疫苗","__modelname__": "问题","endDate": "2010-09-13T00:00:00Z","__documentid__": "d982c117-43c3-407f-bd9e-27dc59008938"}],[{"name": "足部截肢(程序)",评论":空，provider_institution":空，"date_performed": "2014-10-22T00:00:00Z","name_value": "无","__modelname__": "程序","__documentid__": "221df5bd-16a8-4763-9827-06fb305b91e5",provider_name":空，"name_abbrev": "180030006","name_type": "http://purl.bioontology.org/ontology/SNOMEDCT/",位置":空}]]
到 Python 代码中的 XML 文件或 RDF.我没有找到关于 rdf 的帖子，所以我尝试了 XML.我还尝试将列表更改为 dict 就像这篇文章:
但它不起作用.在 views.py 我有:
fileroot = '[{"patient_id":"'+record_id+'"},'+content0+','+content1+','+content2+']'jsonData = simplejson.loads(fileroot)它返回没有属性items"的list"对象.如果我将其更改为:
fileroot = '[{"patient_id":"'+record_id+'"},'+content0+','+content1+','+content2+']'jsonData = simplejson.loads(fileroot)[0]它什么都不返回.我也从这个链接试过:
https://www.safaribooksonline.com/library/view/python-cookbook-3rd/9781449357337/ch06s05.html
但它不再起作用了.
解决方案
这会将您的 json 对象转换为 xml
import simplejsoncontent = simplejson.loads(YourJsonObject)从 xml.etree.ElementTree 导入元素从 xml.etree.ElementTree 导入到字符串def dict_to_xml(tag, d):'''将简单的键/值对字典转换为 XML'''elem = 元素(标签)对于键，d.items() 中的 val:孩子 = 元素(键)child.text = str(val)elem.append(child)返回元素对于范围内的 i(1,len(content)):e = dict_to_xml('SomeNode',content[i][0])# 打印 e打印字符串(e)I am trying to save this json object:
[
{
"patient_id": "59b70b0e-51cb-4215-b65a-db470067c8de"
},
[
{
"tel_1_preferred_p": true,
"adr_region": "OK",
"tel_2_number": "800-979-6786",
"__modelname__": "Demographics",
"adr_city": "Bixby",
"ethnicity": null,
"adr_postalcode": "74008",
"name_family": "John",
"name_middle": null,
"tel_1_type": "h",
"tel_2_type": "c",
"name_prefix": null,
"email": "william.robinson@example.com",
"name_given": "Smith",
"adr_street": "23 Church Rd",
"bday": "1965-08-09",
"__documentid__": "65cd1101-b047-4ce5-afc0-778d033229ca",
"tel_1_number": "800-870-3011",
"preferred_language": "EN",
"gender": "male",
"name_suffix": null,
"tel_2_preferred_p": true,
"race": null,
"adr_country": "USA"
}
],
[
{
"startDate": "2014-10-02T00:00:00Z",
"name_identifier": "195967001",
"name_system": null,
"notes": "None",
"name_title": "Asthma",
"__modelname__": "Problem",
"endDate": "2014-10-13T00:00:00Z",
"__documentid__": "eaba4e92-3aaf-4d8c-a7db-8cfd563290c6"
},
{
"startDate": "2014-12-02T00:00:00Z",
"name_identifier": "161155000",
"name_system": null,
"notes": "None",
"name_title": "School problem (finding)",
"__modelname__": "Problem",
"endDate": "2014-12-14T00:00:00Z",
"__documentid__": "3058b12d-434d-48da-8b14-05dd485946cb"
},
{
"startDate": "2008-07-29T00:00:00Z",
"name_identifier": "185903001",
"name_system": "http://purl.bioontology.org/ontology/SNOMEDCT/",
"notes": null,
"name_title": "Needs influenza immunization",
"__modelname__": "Problem",
"endDate": "2010-09-13T00:00:00Z",
"__documentid__": "d982c117-43c3-407f-bd9e-27dc59008938"
}
],
[
{
"name": "Amputation of the foot (procedure)",
"comments": null,
"provider_institution": null,
"date_performed": "2014-10-22T00:00:00Z",
"name_value": "None",
"__modelname__": "Procedure",
"__documentid__": "221df5bd-16a8-4763-9827-06fb305b91e5",
"provider_name": null,
"name_abbrev": "180030006",
"name_type": "http://purl.bioontology.org/ontology/SNOMEDCT/",
"location": null
}
]
]
to an XML file or RDF in python code. I didn't find posts about rdf so I tried for XML. I tried also to change the list to dict like in this post:
Python Json loads() returning string instead of dictionary?
but it is not working. In views.py I have:
fileroot = '[{"patient_id":"'+record_id+'"},'+content0+','+content1+','+content2+']'
jsonData = simplejson.loads(fileroot)
It returns 'list' object has no attribute 'items'. And if I change it to :
fileroot = '[{"patient_id":"'+record_id+'"},'+content0+','+content1+','+content2+']'
jsonData = simplejson.loads(fileroot)[0]
It returns nothing. I also tried from this link:
https://www.safaribooksonline.com/library/view/python-cookbook-3rd/9781449357337/ch06s05.html
but it is not working again.
解决方案
This will tranlsate your json object to xml
import simplejson
content = simplejson.loads(YourJsonObject)
from xml.etree.ElementTree import Element
from xml.etree.ElementTree import tostring
def dict_to_xml(tag, d):
'''
Turn a simple dict of key/value pairs into XML
'''
elem = Element(tag)
for key, val in d.items():
child = Element(key)
child.text = str(val)
elem.append(child)
return elem
for i in range(1,len(content)):
e = dict_to_xml('SomeNode',content[i][0])
# print e
print tostring(e)
这篇关于Python 中的 Json 到 RDF/XML 文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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