反应警告:函数作为反应孩子无效 [英] React warning: Functions are not valid as a React child

问题描述

我有这个反应组件.这不是正确渲染，而是收到诸如

之类的烦人警告

函数作为 React 子元素无效.如果您返回 Component 而不是从渲染中返回，则可能会发生这种情况.或者，您可能打算调用此函数而不是返回它.

这是我的组件.我在这里做错了什么?

import React, { Component } from 'react';类 Squares 扩展组件 {构造函数(道具){超级(道具)；this.createSquare = this.createSquare.bind(this);}创建方(){让缩进 = []，行 = this.props.rows，cols = this.props.cols;让 squareSize = 50;for (让 i = 0; i < 行; i++) {for (让 j = 0; i < cols; j++) {让 topPosition = j * squareSize;让 leftPosition = i * squareSize;让 divStyle = {顶部:topPosition+'px',左:leftPosition+'px'};indents.push(<div style={divStyle}></div>);}}返回缩进；}使成为() {返回 (<div>{this.createSquare()}

);}}导出默认方块；

更新

@Ross Allen - 进行更改后，渲染方法似乎处于无限循环中，可能会导致内存崩溃

解决方案

您需要调用 createSquare，现在您只是传递对函数的引用.后面加括号:

render() {返回 (<div>{this.createSquare()}

);}

I have this react component. This is not rendering properly but getting an annoying warning like

Functions are not valid as a React child. This may happen if you return a Component instead of from the render. Or maybe you meant to call this function rather than return it.

Here's my component. What am I doing wrong here?

import React, { Component } from 'react';

class Squares extends Component {   

    constructor(props){
        super(props);
        this.createSquare = this.createSquare.bind(this);
    }

    createSquare() {
        let indents = [], rows = this.props.rows, cols = this.props.cols;
        let squareSize = 50;
        for (let i = 0; i < rows; i++) {
            for (let j = 0; i < cols; j++) {
                let topPosition = j * squareSize;
                let leftPosition = i * squareSize;
                let divStyle = {
                    top: topPosition+'px', 
                    left: leftPosition+'px'
                };
                indents.push(<div style={divStyle}></div>);
            }   
          }
        return indents;
    }    

    render() {
      return (
        <div>
            {this.createSquare()}
        </div>
      );
    }
}

export default Squares;

UPDATE

@Ross Allen - After making that change, the render method seems to be in infinite loop with potential memory crash

解决方案

You need to call createSquare, right now you're just passing a reference to the function. Add parentheses after it:

render() {
  return (
    <div>
      {this.createSquare()}
    </div>
  );
}

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