警告:渲染不同组件时无法更新组件.ReactRedux.Consumer [英] Warning: Cannot update a component while rendering a different component. ReactRedux.Consumer

问题描述

我在我的网络应用程序中收到一条警告，并且已经阅读了很多关于该问题的帖子.不幸的是，我还没有设法解决我的问题，希望有人能给我一些建议.据我所知，我需要找到一种在 useEffect 中分派到商店的方法.但到目前为止，我的努力都没有成功.

I am getting a warning in my web app and have read a lot of posts about the issue. Unfortunately I have not managed to resolve my problem and hope someone might have some advice. From what I can tell I need to find a way of dispatching to the store in a useEffect. But my efforts so far have been unsuccessful.

警告说:

index.js:1 警告:在渲染不同的组件 (ReactRedux.Consumer) 时无法更新组件 (Connect(TabMenuComponent)).要在 ReactRedux.Consumer 中找到错误的 setState() 调用，请按照 https://reactjs.org/link/setstate-in-render

index.js:1 Warning: Cannot update a component (Connect(TabMenuComponent)) while rendering a different component (ReactRedux.Consumer). To locate the bad setState() call inside ReactRedux.Consumer, follow the stack trace as described in https://reactjs.org/link/setstate-in-render

堆栈跟踪进一步将我指向此文件.它指向第 30 行，即 store.dispatch 行:

The stack trace further points me to this file. It points to line 30 which is the store.dispatch line:

export const AuthRoute = ({ component: Component, roles, computedMatch, ignoreRedirection, ...rest }) => (
  <Route exact {...rest} render={props => {
    return <ReactReduxContext.Consumer>
      {({ store }) => {
        const user = store.getState().appData.user;

        if (!user) {
          auth.setRedirectUrl(window.location.pathname);
          return <Redirect to={auth.loginUrl} />;
        }

        const redirectUrl = auth.getRedirectUrl();

        if (redirectUrl && !ignoreRedirection) {
          auth.removeRedirectUrl();
          return <Redirect to={redirectUrl} />;
        }

        if (roles && roles.length && !roles.some(neededRole => user.roles.some(userRole => userRole === neededRole))) {
          return <BaseLayout authError={stringKeys.error.unauthorized}></BaseLayout>;
        }

        store.dispatch({ type: "ROUTE_CHANGED", url: computedMatch.url, path: computedMatch.path, params: computedMatch.params })
        return <Component {...props} />;

      }}
    </ReactReduxContext.Consumer>;
  }
  } />
);

推荐答案

您在渲染过程中分派了一个不正确的动作.你应该做的是为你的输入组件创建一个 HOC 或一个包装组件，并在你的组件安装后分派动作

You are dispatching an action in the middle of a render which is not correct. What you should instead do is to create an HOC or a wrapper component to your input Component and dispatch the action once thee component is mounted

使用类组件包装器:

class CompWithDispatch extends React.Component {
   componentDidMount()  {
    const { store, type, url, path, params } = this.props;
    store.dispatch({ type, url, path, params })
   }

   render() {
      const { store, type, url, path, params , component: Component,  ...rest} = this.props;
      return <Component {...rest} />
   }
}
 

带函数组件包装器

const CompWithDispatch = (props) => {
    const { store, type, url, path, params, component:Component, ...rest } = props;
    useEffect(() => {
       store.dispatch({ type, url, path, params })
    }, []);
    return <Component {...rest} />

}

并像使用它一样

export const AuthRoute = ({ component, roles, computedMatch, ignoreRedirection, ...rest }) => (
  <Route exact {...rest} render={props => {
    return <ReactReduxContext.Consumer>
      {({ store }) => {
        const user = store.getState().appData.user;

        if (!user) {
          auth.setRedirectUrl(window.location.pathname);
          return <Redirect to={auth.loginUrl} />;
        }

        const redirectUrl = auth.getRedirectUrl();

        if (redirectUrl && !ignoreRedirection) {
          auth.removeRedirectUrl();
          return <Redirect to={redirectUrl} />;
        }

        if (roles && roles.length && !roles.some(neededRole => user.roles.some(userRole => userRole === neededRole))) {
          return <BaseLayout authError={stringKeys.error.unauthorized}></BaseLayout>;
        }

        const additionalProps = { type: "ROUTE_CHANGED", url: computedMatch.url, path: computedMatch.path, params: computedMatch.params })
        return <CompWithDispatch {...additionalProps} {...props} component={component}/>;

      }}
    </ReactReduxContext.Consumer>;
  }
  } />
);

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