在 React-router v4 中嵌套路由和动态路由 [英] Nesting routes and dynamically routing in React-router v4
问题描述
我有以下路由配置:
return (<路由器><div><Route path='/login' component={LoginPage}/><EnsureLoggedInContainer><Route path='/abc' component={abc}/></EnsureLoggedInContainer></路由器>
);
EnsureLoggedInContainer 是:
从'react'导入React;从react-redux"导入{连接};类EnsureLoggedInContainer 扩展了React.Component{componentDidMount() {如果(!this.props.isLoggedIn){//this.props.history.push('/login');this.context.router.push('/contact');}}使成为() {//console.log(this.props);如果( this.props.isLoggedIn ){返回 this.props.children;}别的{返回空;}}}const mapStateToProps = (state,ownProps) =>{返回{isLoggedIn : state.isLoggedIn,//当前URL : this.props}}导出默认连接(mapStateToProps)(EnsureLoggedInContainer);
但是,历史推送:this.props.history.push('/login');
不起作用.这里没有历史记录.
如果我使用这样的配置:
<Route path='/myjs' component={MyjsPage}/></路线>
我遇到如下问题:
警告:你不应该使用<路由组件>和<路由子项>在同一条路线上;<路由子项>将被忽略
reactjs 中最好的身份验证方式是什么?
从我看到的你的 React Router Design 来看,你似乎使用的是 React 路由器版本 4
在这种情况下,您可以在组件本身中指定路由,并使用 withRouter 进行动态重定向,如
return (<路由器><div><Route path='/login' component={LoginPage}/><EnsureLoggedInContainer/></路由器>
);
和
从'react'导入React;从react-redux"导入{连接};从反应路由器"导入{withRouter};类EnsureLoggedInContainer 扩展了React.Component{componentDidMount() {如果(!this.props.isLoggedIn){this.props.history.push('/登录');}}使成为() {//console.log(this.props);如果( this.props.isLoggedIn ){return <Route path='/abc' component={abc}/>}别的{返回空;}}}const mapStateToProps = (state,ownProps) =>{返回{isLoggedIn : state.isLoggedIn,//当前URL : this.props}}导出默认连接(mapStateToProps)(withRouter(EnsureLoggedInContainer));
I have following routing configuration:
return (<div>
<Router>
<div>
<Route path='/login' component={LoginPage}/>
<EnsureLoggedInContainer>
<Route path='/abc' component={abc} />
</EnsureLoggedInContainer>
</div>
</Router>
</div>
);
The EnsureLoggedInContainer is:
import React from 'react';
import { connect } from "react-redux";
class EnsureLoggedInContainer extends React.Component
{
componentDidMount() {
if ( !this.props.isLoggedIn )
{
// this.props.history.push('/login');
this.context.router.push('/contact');
}
}
render() {
// console.log(this.props);
if ( this.props.isLoggedIn )
{
return this.props.children;
}
else
{
return null;
}
}
}
const mapStateToProps = (state,ownProps) => {
return{
isLoggedIn : state.isLoggedIn,
// currentURL : this.props
}
}
export default connect(mapStateToProps)(EnsureLoggedInContainer);
But, the history push: this.props.history.push('/login');
isn't working. Here history is not present.
If I am using a configuration like this:
<Route component={EnsureLoggedInContainer}>
<Route path='/myjs' component={MyjsPage} />
</Route>
I am getting issue like:
Warning: You should not use <Route component> and <Route children> in the same route; <Route children> will be ignored
What's the best way of authentication in reactjs?
From what I can see of your React Router Design, you seem to be using React router version 4
In that case you can specify the route in the Component Itself, and make use of withRouter to do a dynamic redirect like
return (<div>
<Router>
<div>
<Route path='/login' component={LoginPage}/>
<EnsureLoggedInContainer/>
</div>
</Router>
</div>
);
and
import React from 'react';
import { connect } from "react-redux";
import {withRouter} from "react-router";
class EnsureLoggedInContainer extends React.Component
{
componentDidMount() {
if ( !this.props.isLoggedIn )
{
this.props.history.push('/login');
}
}
render() {
// console.log(this.props);
if ( this.props.isLoggedIn )
{
return <Route path='/abc' component={abc} />
}
else
{
return null;
}
}
}
const mapStateToProps = (state,ownProps) => {
return{
isLoggedIn : state.isLoggedIn,
// currentURL : this.props
}
}
export default connect(mapStateToProps)(withRouter(EnsureLoggedInContainer));
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