在多维数组ç怪异数组语法 [英] C weird array syntax in multi-dimensional arrays

问题描述

我知道这是真实的：

  X [4] == 4 [X]
 

什么是相当于多维数组？是下面的是真的吗？

  X [4] [3] == 3 [X [4] == 3 [4 [X]]
 

解决方案

X [Y] 定义为 *（X +（Y） ）

X [Y] [Z] 将成为 *（*（X +（Y））+ Z）

X [Y [Z]] 将成为 *（X +（*（Y +（Z））））

---

X [4] [3] 将成为 *（*（X +（4））+ 3） 将成为 *（*（X + 4）+ 3）

3 [X [4]] 将成为 *（3 +（*（X +（4））））将成为 *（*（X + 4）+ 3）

3 [4 [X] 将成为 *（3 +（*（4 +（X））））将成为 *（*（X + 4）+ 3）

这意味着它们都是等价的。

I've known that this is true:

x[4] == 4[x]

What is the equivalent for multi-dimensional arrays? Is the following true?

x[4][3] == 3[x[4]] == 3[4[x]]

解决方案

x[y] is defined as *(x + (y))

x[y][z] would become *(*(x + (y)) + z)

x[y[z]] would become *(x + (*(y + (z))))

---

x[4][3] would become *(*(x + (4)) + 3) would become *(*(x + 4) + 3)

3[x[4]] would become *(3 + (*(x + (4)))) would become *(*(x + 4) + 3)

3[4[x]] would become *(3 + (*(4 + (x)))) would become *(*(x + 4) + 3)

Which means they are all equivalent.

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