反应钩子“useSelector"在函数中调用 [英] React Hook "useSelector" is called in function

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本文介绍了反应钩子“useSelector"在函数中调用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我无法弄清楚useSelector"发生了什么,我需要一点帮助.

I cannot figure out what going on with "useSelector" I need little help, please.

错误

React Hook "useSelector" 在函数 "render_user" 中调用,该函数既不是 React 函数组件,也不是自定义的 React Hook 函数

React Hook "useSelector" is called in function "render_user" which is neither a React function component or a custom React Hook function

class Navigationbar extends Component {

  onLogoutClick = e => {
    e.preventDefault();
    this.props.logoutUser(); //this.props.
  };

  render() {
      const render_user = () => {

        const auth = useSelector(state => state.auth); Error Message is here
        //More Code Here
      );
    };
  } 

Navigationbar.propTypes = {
  logoutUser: PropTypes.func.isRequired,
  auth: PropTypes.object.isRequired
};

const mapStateToProps = state => ({
  auth: state.auth
});

export default connect(
  mapStateToProps,
  { logoutUser }
)(Navigationbar);

推荐答案

该错误是由于您违反了 钩子规则:

The error is due to the fact that you violated the rules of hooks:

  • 仅在顶层调用挂钩
  • 仅从 React 函数调用钩子

违规行为:

  1. useSelector() 不在顶层调用.它在 render() 中的 render_user() 中调用(即嵌套函数).
  2. useSelector() 是类组件的一部分,Navigationbar
  1. useSelector() is not called in top-level. It is called in render_user() in render() (i.e nested function).
  2. useSelector() is part of a class component, Navigationbar

你可以提取一个组件来遵循钩子的规则并使用useSelector:

You can extract a component to follow the rules of hooks and make use of useSelector:

function User() { // Rule 2: call hooks in function component
  const auth = useSelector(state => state.auth); // Rule 1: call hooks in top-level
  return <>{auth}</>
}

class Navigationbar extends Component {

  render_user() {
    if (props.authenticated) {
      return <User />
    }
    // not yet authenticated
    // do something else
  }

  render() {
    return <>{this.render_user()}</>
  }
}

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