aifc 模块错误:Python 不会打开文件 [英] aifc module Error: Python won't open file

问题描述

我刚刚开始使用 python，所以请耐心等待；)

I'm just getting started with python so please bear with me ;)

在遵循基本教程时，我在打开文件时遇到了问题，这是回溯:

While following a basic tutorial I ran into a problem while opening a file, here's the traceback:

File "/home/nick/Dropbox/workspace/pytest/schlange.py", line 55, in <module>
        f=open("file.csv","r")   
File "/usr/lib/python2.6/aifc.py", line 922, in open
        return Aifc_read(f)   
File "/usr/lib/python2.6/aifc.py", line 335, in __init__
        self.initfp(f)   
File "/usr/lib/python2.6/aifc.py", line 288, in initfp
        raise Error, 'file does not start with FORM id' 
aifc.Error: file does not start with FORM id

这是否意味着我的 Python 安装中的aifc.py"已损坏，或者我是否错过了此处的重要内容?

Does that mean that 'aifc.py' in my python installation is broken or did I miss something important here?

推荐答案

您已决定从 aifc 及其 open()<导入 */code> 隐藏了内置的 open().这就是我们不导入 * 的原因.而是导入模块本身，并在需要时使用引用来获取其名称，例如aifc.open().

You've decided to import * from aifc, and its open() has shadowed the built-in open(). This is why we don't import *. Import the module itself instead and use the reference to get to its names when required, e.g. aifc.open().

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