Scala中二叉树的尾递归最大深度方法 [英] Tail recursive maximum depth method of binary tree in Scala

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问题描述

我写了一个方法来计算二叉树的最大深度.

我想写一个尾递归方法.

我想过使用列表,但没有找到解决方案

这是我的非尾递归方法:

def 深度:Int = {def iter(f: FormulaWff): Int = f match {case Var(_) =>0case Not(e1) =>1 + 迭代(e1)情况 And(e1, e2) =>1 + Math.max(iter(e1), iter(e2))case Or(e1, e2) =>1 + Math.max(iter(e1), iter(e2))case 暗示(e1, e2) =>1 + Math.max(iter(e1), iter(e2))}迭代(这个)}

解决方案

试试

import scala.util.control.TailCalls.{TailRec, done, tailcall}特质公式Wff {定义深度:Int = {def iter(f: FormulaWff): TailRec[Int] = {def hlp(e1: FormulaWff, e2: FormulaWff): TailRec[Int] = for {x <- 尾调用(iter(e1))y <- 尾调用(iter(e2))} 产量 1 + Math.max(x, y)f 匹配 {case Var(_) =>完成(0)case Not(e1) =>为了 {x <- 尾调用(iter(e1))} 产量 1 + x情况 And(e1, e2) =>帮助(e1,e2)case Or(e1, e2) =>帮助(e1,e2)case 暗示(e1, e2) =>帮助(e1,e2)}}iter(this).result}}案例类 Var(s: String) 扩展了 FormulaWff案例类 Not(e: FormulaWff) 扩展了 FormulaWff案例类 And(e1: FormulaWff, e2: FormulaWff) 扩展了 FormulaWffcase class Or(e1: FormulaWff, e2: FormulaWff) 扩展了 FormulaWffcase class Implies(e1: FormulaWff, e2: FormulaWff) 扩展了 FormulaWff

<小时>

直接解决

 密封性状 FormulaWff最终案例类 Var(s: String) 扩展了 FormulaWff最终案例类 Not(e: FormulaWff) 扩展了 FormulaWff最终案例类 And(e1: FormulaWff, e2: FormulaWff) 扩展了 FormulaWff最后一个案例类 Or(e1: FormulaWff, e2: FormulaWff) 扩展了 FormulaWff最后一个案例类 Implies(e1: FormulaWff, e2: FormulaWff) 扩展了 FormulaWff密封性状 结果case 对象 NotExpanded 扩展结果case 对象扩展扩展结果最终案例类Calculated(value: Int) extends Result最终案例类框架(参数:FormulaWff,资源:结果)def depth(f: FormulaWff): Int = step1(List(Frame(f, NotExpanded))) 匹配{case Frame(arg,Calculated(res))::Nil =>资源}@tailrecdef step1(stack: List[Frame]): List[Frame] = {val x = step(stack, Nil)x 匹配 {case Frame(arg,Calculated(res))::Nil =>X案例_ =>步骤1(x)}}@tailrecdef step(stack: List[Frame], acc: List[Frame]): List[Frame] = {堆栈匹配{case Frame(_,Calculated(res1))::Frame(_,Calculated(res2))::Frame(And(e1,e2),Expanded)::frames=>step(frames, Frame(And(e1, e2), Calculated(1 + math.max(res1, res2))) :: acc)case Frame(_,Calculated(res1))::Frame(_,Calculated(res2))::Frame(Or(e1,e2),Expanded)::frames=>step(frames, Frame(Or(e1, e2), Calculated(1 + math.max(res1, res2))) :: acc)case Frame(_,Calculated(res1))::Frame(_,Calculated(res2))::Frame(Implies(e1,e2),Expanded)::frames=>step(frames, Frame(Implies(e1, e2), Calculated(1 + math.max(res1, res2))) :: acc)case Frame(_,Calculated(res1))::Frame(Not(e1),Expanded)::frames =>step(frames, Frame(Not(e1), Calculated(1 + res1)) :: acc)case Frame(Var(s), _) :: 帧 =>step(frames, Frame(Var(s),Calculated(0))::acc)case Frame(Not(e1), NotExpanded)::frames =>step(frames, Frame(Not(e1), Expanded) :: Frame(e1, NotExpanded) :: acc)case Frame(And(e1, e2), NotExpanded)::frames =>step(frames, Frame(And(e1, e2), Expanded) :: Frame(e1, NotExpanded) :: Frame(e2, NotExpanded) :: acc)case Frame(Or(e1, e2), NotExpanded) :: frames =>step(frames, Frame(Or(e1, e2), Expanded) :: Frame(e1, NotExpanded) :: Frame(e2, NotExpanded) :: acc)case Frame(Implies(e1, e2), NotExpanded)::frames =>step(frames, Frame(Implies(e1, e2), Expanded) :: Frame(e1, NotExpanded) :: Frame(e2, NotExpanded) :: acc)case Frame(arg, Expanded) :: 帧 =>step(frames, Frame(arg, Expanded) :: acc)case Frame(arg,Calculated(res))::frames =>step(frames, Frame(arg,Calculated(res))::acc)情况为零 =>反向}}

如何使树映射尾递归?>

I wrote a method to calculate the maximum depth of a binary tree.

I would like to write a tail recursive method.

I thought of using lists, but I didn't find solutions

This is my method that is not tail recursive:

def depth: Int = {

    def iter(f: FormulaWff): Int = f match {
      case Var(_) => 0
      case Not(e1) => 1 + iter(e1)
      case And(e1, e2)  => 1 + Math.max(iter(e1), iter(e2))
      case Or(e1, e2) => 1 + Math.max(iter(e1), iter(e2))
      case Implies(e1, e2) => 1 + Math.max(iter(e1), iter(e2))
    }

    iter(this)
  }

解决方案

Try

import scala.util.control.TailCalls.{TailRec, done, tailcall}

trait FormulaWff {
  def depth: Int = {
    def iter(f: FormulaWff): TailRec[Int] = {
      def hlp(e1: FormulaWff, e2: FormulaWff): TailRec[Int] = for {
        x <- tailcall(iter(e1))
        y <- tailcall(iter(e2))
      } yield 1 + Math.max(x, y)

      f match {
        case Var(_) => done(0)
        case Not(e1) => for {
          x <- tailcall(iter(e1))
        } yield 1 + x
        case And(e1, e2) => hlp(e1, e2)
        case Or(e1, e2) => hlp(e1, e2)
        case Implies(e1, e2) => hlp(e1, e2)
      }
    }

    iter(this).result
  }
}

case class Var(s: String) extends FormulaWff
case class Not(e: FormulaWff) extends FormulaWff
case class And(e1: FormulaWff, e2: FormulaWff) extends FormulaWff
case class Or(e1: FormulaWff, e2: FormulaWff) extends FormulaWff
case class Implies(e1: FormulaWff, e2: FormulaWff) extends FormulaWff


Direct solution

  sealed trait FormulaWff
  final case class Var(s: String) extends FormulaWff
  final case class Not(e: FormulaWff) extends FormulaWff
  final case class And(e1: FormulaWff, e2: FormulaWff) extends FormulaWff
  final case class Or(e1: FormulaWff, e2: FormulaWff) extends FormulaWff
  final case class Implies(e1: FormulaWff, e2: FormulaWff) extends FormulaWff

  sealed trait Result
  case object NotExpanded extends Result
  case object Expanded extends Result
  final case class Calculated(value: Int) extends Result

  final case class Frame(arg: FormulaWff, res: Result)

  def depth(f: FormulaWff): Int = step1(List(Frame(f, NotExpanded))) match {
    case Frame(arg, Calculated(res)) :: Nil => res
  }

  @tailrec
  def step1(stack: List[Frame]): List[Frame] = {
    val x = step(stack, Nil)
    x match {
      case Frame(arg, Calculated(res)) :: Nil => x
      case _ => step1(x)
    }
  }

  @tailrec
  def step(stack: List[Frame], acc: List[Frame]): List[Frame] = {
    stack match {
      case Frame(_, Calculated(res1)) :: Frame(_, Calculated(res2)) :: Frame(And(e1, e2), Expanded) :: frames =>
        step(frames, Frame(And(e1, e2), Calculated(1 + math.max(res1, res2))) :: acc)
      case Frame(_, Calculated(res1)) :: Frame(_, Calculated(res2)) :: Frame(Or(e1, e2), Expanded) :: frames =>
        step(frames, Frame(Or(e1, e2), Calculated(1 + math.max(res1, res2))) :: acc)
      case Frame(_, Calculated(res1)) :: Frame(_, Calculated(res2)) :: Frame(Implies(e1, e2), Expanded) :: frames =>
        step(frames, Frame(Implies(e1, e2), Calculated(1 + math.max(res1, res2))) :: acc)
      case Frame(_, Calculated(res1)) :: Frame(Not(e1), Expanded) :: frames =>
        step(frames, Frame(Not(e1), Calculated(1 + res1)) :: acc)
      case Frame(Var(s), _) :: frames =>
        step(frames, Frame(Var(s), Calculated(0)) :: acc)

      case Frame(Not(e1), NotExpanded) :: frames =>
        step(frames, Frame(Not(e1), Expanded) :: Frame(e1, NotExpanded) :: acc)
      case Frame(And(e1, e2), NotExpanded) :: frames =>
        step(frames, Frame(And(e1, e2), Expanded) :: Frame(e1, NotExpanded) :: Frame(e2, NotExpanded) :: acc)
      case Frame(Or(e1, e2), NotExpanded) :: frames =>
        step(frames, Frame(Or(e1, e2), Expanded) :: Frame(e1, NotExpanded) :: Frame(e2, NotExpanded) :: acc)
      case Frame(Implies(e1, e2), NotExpanded) :: frames =>
        step(frames, Frame(Implies(e1, e2), Expanded) :: Frame(e1, NotExpanded) :: Frame(e2, NotExpanded) :: acc)

      case Frame(arg, Expanded) :: frames => step(frames, Frame(arg, Expanded) :: acc)
      case Frame(arg, Calculated(res)) :: frames => step(frames, Frame(arg, Calculated(res)) :: acc)

      case Nil => acc.reverse
    }
  }

How to make tree mapping tail-recursive?

这篇关于Scala中二叉树的尾递归最大深度方法的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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