对象的滤镜阵列由对象键 [英] Filter array of objects by object key

问题描述

我对象在Javascript数组：

  VAR列表= [
            {
                员工：'乔'，
                类型：'假期'，
            }，
            {
                员工：杰里，
                类型：'研讨会'，            }，
            {
                员工：'乔'，
                输入：'上岸'，
            }
           ];
 

我想获得对象的两个新的阵列;一个关键员工乔，另一个关键员工杰里。该对象应该保持相同的对键/值。

我一直在试图让使用underscore.js一个解决方案，但它越来越太复杂了。如何可以做到这一点任何想法？

在此先感谢

解决方案

  VAR的emps = {};
_.each（列表，功能（项目）{
   EMPS [item.employee] = EMPS [item.employee] || [];
   EMPS [item.employee] .push（项目）;
}）;
 

或使用 GROUPBY

  VAR的emps = _.groupBy（表，函数（项目）{
   返回item.employee;
}）;
 

的console.log（EMPS）; 给

  {
    杰里：[
        {
            员工：杰里
            类型：研讨会
        }
    ]
    乔：[
        {
            员工：乔，
            类型：假日
        }，
        {
            员工：乔，
            类型：上岸
        }
    ]
}
 

I have an array of objects in Javascript:

var List = [
            {
                employee:'Joe',
                type:'holiday',
            },
            {
                employee:'Jerry',
                type:'seminar',

            },
            {
                employee:'Joe',
                type:'shore leave',
            }
           ];

I would like to obtain two new arrays of objects; one for the key employee "Joe" and the other for the key employee "Jerry". The objects should keep the same pairs of key/values.

I have been trying to get a solution using underscore.js, but it is getting too complicated. Any ideas on how this can be achieved?

Thanks in advance

解决方案

var emps = {};  
_.each(List, function(item){
   emps[item.employee] = emps[item.employee] || [];
   emps[item.employee].push(item);
});

or using groupBy

var emps = _.groupBy(List, function(item){
   return item.employee;
});

console.log(emps); gives

{
    "Jerry": [
        {
            "employee": "Jerry",
            "type": "seminar"
        }
    ],
    "Joe": [
        {
            "employee": "Joe",
            "type": "holiday"
        },
        {
            "employee": "Joe",
            "type": "shore leave"
        }
    ]
}

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