无法获得 Python 可调用对象的 argspec? [英] Can't get argspec for Python callables?

问题描述

我正在玩可调用的 Python.基本上你可以定义一个 python 类并实现 __call__ 方法来使这个类的实例可调用.例如，

I'm playing with Python callable. Basically you can define a python class and implement __call__ method to make the instance of this class callable. e.g.,

class AwesomeFunction(object):
    def __call__(self, a, b):
        return a+b

模块检查有一个函数getargspec，它给你一个函数的参数说明.但是，似乎我不能在可调用对象上使用它:

Module inspect has a function getargspec, which gives you the argument specification of a function. However, it seems I cannot use it on a callable object:

fn = AwesomeFunction()
import inspect
inspect.getargspec(fn)

不幸的是，我遇到了类型错误:

Unfortunately, I got a TypeError:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.6/inspect.py", line 803, in getargspec
    raise TypeError('arg is not a Python function')
TypeError: arg is not a Python function

我认为您不能将任何可调用对象视为函数是非常不幸的，除非我在这里做错了什么?

I think it's quite unfortunate that you can't treat any callable object as function, unless I'm doing something wrong here?

推荐答案

如果你需要这个功能，写一个包装函数来检查fn是否有一个属性__call__，如果是，则将其 __call__ 函数传递给 getargspec.

If you need this functionality, it is absolutely trivial to write a wrapper function that will check to see if fn has an attribute __call__ and if it does, pass its __call__ function to getargspec.

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