尝试使用反射查找不为空的对象中的所有集合 [英] Trying to find all collections in an object not null with reflection
问题描述
我正在尝试构建一个通用的单元测试方法,以确保我们所有的对象都在初始化它们作为构造函数集合的属性.我没有手动检查每个属性的断言,然后考虑是否修改了类对象,我想使用反射.问题在于集合,并不仅仅是List,而是类的类副本,然后继承List.
I am trying to build a generic unit test method, to make sure all of our objects are initiliazing their properties that are collections on the constructor. I instead of manually checking with assert on each property, and then thinking ahaed if a class object is modified, I wanted to use reflection. The problem is that the collections, and not just List, but a class copy of the class, and then inherit List.
所以,我们可能有如下内容:
So, we may have somthing like the following:
public class PaymentType
{
int Id{get;set;}
PaymentTypeCollection PaymentTypeCollection {get;set;}
}
public class PaymentTypeCollection : List<PaymentType>
{
//som ecustom stuff here
}
现在的问题是,当您从 PaymentType 类中迭代对象的属性,并尝试使用以下检查执行反射方法时,它返回 false,并且可以理解.
Now the problem is that when you itterate over the properties of the object from class PaymentType, and try to do a reflection method with the following check, it comes back false, and understandably.
foreach (var prop in objectType.GetProperties())
{
// test if property is IEnumerable<T>? This comes back as false
if (typeof(IEnumerable<>).IsAssignableFrom(prop.PropertyType))
{
//do stuff here
}
}
我该如何解决这个问题.我需要查看该属性是否继承了 IEnumerable?因为类型实际上是 PaymentTypeColelction.我将如何处理?
How could I go about the issue. I need to see if the property, is then inheriting IEnumerable? Since the type would actually be PaymentTypeColelction. How would I handle that?
提前致谢.
推荐答案
使用非通用的 IEnumerable
.泛型的IEnumerable
实现了IEnumerable
,不用担心类型参数.
Use the non-generic IEnumerable
. The generic IEnumerable<out T>
implements IEnumerable
, and you don't have to worry about type arguments.
if (typeof(IEnumerable).IsAssignableFrom(prop.PropertyType))
{
//do stuff here
}
但是要小心,例如string
也实现了IEnumerable
,所以你的方法也会找到string
属性.
But be careful, for example string
also implements IEnumerable<char>
, so your method will also find string
properties.
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