当点击刷新 (F5) 时,C# 验证重复最后一次回传 [英] C# validate repeat last PostBack when hit Refresh (F5)
本文介绍了当点击刷新 (F5) 时,C# 验证重复最后一次回传的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个生成文件的网络表单,但是当我单击生成回发的按钮以生成文件时,如果我按刷新 (F5) 完成,页面会重新提交回发并重新生成文件,有任何方法可以验证它并向用户显示一条消息,或者干脆什么都不做!
i have a webform that generates a file, but when i click the button that produces the postback to generate the file Once it finish if i press Refresh (F5) the page resubmit the postback and regenerates the file, there's any way to validate it and show a message to the user or simply DO NOTHING!
谢谢:)
推荐答案
我为这个问题写了一个解决方案,如果有人需要它就在这里.
i wrote a solution for this problem and here it is if anyone needs it.
protected void Page_Load(object sender, System.EventArgs e)
{
/*******/
//Validate if the user Refresh the webform.
//U will need::
//A global private variable called ""private bool isRefresh = false;""
//a global publica variable called ""public int refreshValue = 0;""
//a html control before </form> tag: ""<input type="hidden" name="ValidateRefresh" value="<%= refreshValue %>">""
int postRefreshValue = 0;
refreshValue = SII.Utils.convert.ToInt(Request.Form["ValidateRefresh"]); //u can use a int.parse()
if (refreshValue == 0)
Session["ValidateRefresh"] = 0;
postRefreshValue = SII.Utils.convert.ToInt(Session["ValidateRefresh"]); //can use a int.parse()
if (refreshValue < postRefreshValue)
isRefresh = true;
Session["ValidateRefresh"] = postRefreshValue + 1;
refreshValue = SII.Utils.convert.ToInt(Session["ValidateRefresh"]); //can use a int.parse()
/********/
if (!IsPostBack)
{
//your code
}
}
你只需要评估:
if (!isRefresh)
PostFile();
else
{
//Error msg you are refreshing
}
这篇关于当点击刷新 (F5) 时,C# 验证重复最后一次回传的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文