正则表达式在第一次匹配时停止 [英] Regular expression to stop at first match

问题描述

我的正则表达式看起来像

My regex pattern looks something like

<xxxx location="file path/level1/level2" xxxx some="xxx">

我只对分配给位置的引号中的部分感兴趣.如果没有贪心开关，它不应该像下面一样简单吗?

I am only interested in the part in quotes assigned to location. Shouldn't it be as easy as below without the greedy switch?

/.*location="(.*)".*/

似乎不起作用.

推荐答案

你需要让你的正则表达式非贪婪，因为默认情况下，"(.*)" 会匹配所有 <代码>文件路径/level1/level2"xxx some="xxx".

You need to make your regular expression non-greedy, because by default, "(.*)" will match all of "file path/level1/level2" xxx some="xxx".

相反，您可以使您的点星不贪婪，这将使其匹配尽可能少的字符:

Instead you can make your dot-star non-greedy, which will make it match as few characters as possible:

/location="(.*?)"/

在量词(?、* 或 +)上添加 ? 使其非贪婪.

Adding a ? on a quantifier (?, * or +) makes it non-greedy.

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