仅匹配空格或字符串开头/结尾之间的整数的正则表达式 [英] Regex that matches integers in between whitespace or start/end of string only

问题描述

我目前正在使用模式:\b\d+\b，使用以下条目对其进行测试:

I'm currently using the pattern: \b\d+\b, testing it with these entries:

numb3r 
2
3454 
3.214
test

我只希望它捕获 2 和 3454.它非常适合捕获数字单词，除了边界标志 (\b) 包括 "." 作为考虑作为一个单独的词.我尝试排除句点，但在编写模式时遇到了麻烦.

I only want it to catch 2, and 3454. It works great for catching number words, except that the boundary flags (\b) include "." as consideration as a separate word. I tried excluding the period, but had troubles writing the pattern.

基本上我想删除整数词，并且只删除它们.

Basically I want to remove integer words, and just them alone.

推荐答案

如果你只想匹配空格，你可以使用环视:

You could use lookaround instead if all you want to match is whitespace:

(?<=\s|^)\d+(?=\s|$)

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