什么是仅匹配空字符串的正则表达式? [英] What is a regex to match ONLY an empty string?
问题描述
有很多关于正则表达式匹配潜在空字符串的帖子,但我找不到任何提供仅匹配空字符串的正则表达式的帖子.
There are lots of posts about regexs to match a potentially empty string, but I couldn't readily find any which provided a regex which only matched an empty string.
我知道 ^
将匹配任何行的开头,而 $
将匹配任何行的结尾以及字符串的结尾.因此,/^$/
比\n"、foobar\n\n"等空字符串匹配的多.
I know that ^
will match the beginning of any line and $
will match the end of any line as well as the end of the string. As such, /^$/
matches far more than the empty string such as "\n", "foobar\n\n", etc.
不过,我会认为 /\A\Z/
只会匹配空字符串,因为 \A
匹配字符串的开头和 \Z
匹配字符串的结尾.但是,我的测试表明 /\A\Z/
也将匹配\n".这是为什么?
I would have thought, though, that /\A\Z/
would match just the empty string, since \A
matches the beginning of the string and \Z
matches the end of the string. However, my testing shows that /\A\Z/
will also match "\n". Why is that?
推荐答案
如 http://www.regular-expressions.info/anchors.html 在以换行符结尾的字符串"部分下,\Z
通常会在字符串中的最后一个换行符结束之前匹配以换行符结尾.如果只想匹配字符串的结尾,则需要使用\z
.此规则的例外是 Python.
As explained in http://www.regular-expressions.info/anchors.html under the section "Strings Ending with a Line Break", \Z
will generally match before the end of the last newline in strings that end in a newline. If you want to only match the end of the string, you need to use \z
. The exception to this rule is Python.
换句话说,要独占匹配一个空字符串,您需要使用/\A\z/
.
In other words, to exclusively match an empty string, you need to use /\A\z/
.
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