为什么忽略大小写标志(re.I)在 re.sub() 中不起作用 [英] Why doesn't ignorecase flag (re.I) work in re.sub()

问题描述

来自pydoc:

re.sub = sub(pattern, repl, string, count=0, flags=0)
返回替换最左边得到的字符串字符串中模式的非重叠出现替代品repl 可以是字符串或可调用的；如果是字符串，则处理其中的反斜杠转义.如果是一个可调用的，它传递了匹配对象并且必须返回要使用的替换字符串.

re.sub = sub(pattern, repl, string, count=0, flags=0)
Return the string obtained by replacing the leftmost non-overlapping occurrences of the pattern in string by the replacement repl. repl can be either a string or a callable; if a string, backslash escapes in it are processed. If it is a callable, it's passed the match object and must return a replacement string to be used.

示例代码:

import re
print re.sub('class', 'function', 'Class object', re.I)

除非我将模式更改为类"，否则不会进行替换.

No replacement is made unless I change pattern to 'Class'.

文档没有提及任何有关此限制的内容，因此我认为我可能做错了什么.

Documentation doesn't mention anything about this limitation, so I assume I may be doing something wrong.

这是怎么回事?

推荐答案

在我看来你应该这样做:

Seems to me that you should be doing:

import re
print(re.sub('class', 'function', 'Class object', flags=re.I))

没有这个，re.I 参数会被传递给 count 参数.

Without this, the re.I argument is passed to the count argument.

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