在 R 中使用 Regex 获取 Twitter @Username [英] Get Twitter @Username with Regex in R
问题描述
如何在 R 中使用正则表达式从文本字符串中提取 Twitter 用户名?
How can I use regex in R to extract Twitter usernames from a string of text?
我试过了
library(stringr)
theString <- '@foobar Foobar! and @foo (@bar) but not foo@bar.com'
str_extract_all(string=theString,pattern='(?:^|(?:[^-a-zA-Z0-9_]))@([A-Za-z]+[A-Za-z0-9_]+)')
但我最终得到了 @foobar、@foo 和 (@bar，其中包含一个不需要的括号.
But I end up with @foobar, @foo and (@bar which contains an unwanted parenthesis.
我怎样才能得到 @foobar、@foo 和 @bar 作为输出?
How can I get just @foobar, @foo and @bar as output?
推荐答案
这是一种在 R 中有效的方法:
Here's one method that works in R:
theString <- '@foobar Foobar! and @foo (@bar) but not foo@bar.com'
theString1 <- unlist(strsplit(theString, " "))
regex <- "(^|[^@\\w])@(\\w{1,15})\\b"
idx <- grep(regex, theString1, perl = T)
theString1[idx]
[1] "@foobar" "@foo" "(@bar)"
如果你想在 R 中使用 @Jerry 的回答:
If you want to use @Jerry's answer in R:
regex <- "@([A-Za-z]+[A-Za-z0-9_]+)(?![A-Za-z0-9_]*\\.)"
idx <- grep(regex, theString1, perl = T)
theString1[idx]
[1] "@foobar" "@foo" "(@bar)"
然而，这两种方法都包含您不想要的括号.
Both of these methods include the parenthesis that you don't want, however.
更新这将使您从头到尾没有括号或任何其他类型的标点符号(下划线除外，因为它们允许在用户名中使用)
UPDATE This will get to you start-to-finish with no parentheses or any other kind of punctuation (except underscores, since they're allowed in usernames)
theString <- '@foobar Foobar! and @fo_o (@bar) but not foo@bar.com'
theString1 <- unlist(strsplit(theString, " "))
regex1 <- "(^|[^@\\w])@(\\w{1,15})\\b" # get strings with @
regex2 <- "[^[:alnum:]@_]" # remove all punctuation except _ and @
users <- gsub(regex2, "", theString1[grep(regex1, theString1, perl = T)])
users
[1] "@foobar" "@fo_o" "@bar"
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