Sed:匹配后打印所有行 [英] Sed : print all lines after match

问题描述

我在使用sed后得到了我的研究结果:

I got my research result after using sed :

zcat file* | sed -e 's/.*text=\(.*\)status=[^/]*/\1/' | cut -f 1 - | grep "pattern"

但它只显示我切割的部分.如何在匹配后打印所有行?

But it only shows the part that I cut. How can I print all lines after a match ?

我使用的是 zcat，所以我不能使用 awk.

I'm using zcat so I cannot use awk.

谢谢.

已

这是我的日志文件:

[01/09/2015 00:00:47]       INFO=54646486432154646 from=steve   idfrom=55516654455457       to=jone       idto=5552045646464 guid=100021623456461451463   n
um=6    text=hi my number is 0 811 22 1/12   status=new      survstatus=new

我的目标是找到所有使用电话号码向我的网站发送垃圾邮件的用户(使用 grep "pattern")，然后打印所有行以获取有关每个垃圾邮件的所有信息.问题是 INFO 或 id 中可能存在匹配项，因此我使用 sed 来先获取文本.

My aim is to find all users that spam my site with their telephone numbers (using grep "pattern") then print all the lines to get all the information about each spam. The problem is there may be matches in INFO or id, so I use sed to get the text first.

推荐答案

也许这就是您真正想要的?查找匹配pattern"的行并提取 text= 之后的字段，直到 status=?

Maybe this is what you actually want? Find lines matching "pattern" and extract the field after text= up through just before status=?

zcat file* | sed -e '/pattern/s/.*text=\(.*\)status=[^/]*/\1/'

你没有透露 pattern 实际上是什么——如果它是一个变量，你不能在它周围使用单引号.

You are not revealing what pattern actually is -- if it's a variable, you cannot use single quotes around it.

注意 \(.*\)status=[^/]* 将通过 survstatus=new 在您的示例中匹配.那可能不是您想要的?似乎任何地方都没有 status= 后跟斜杠——你真的应该更详细地解释你真正想要完成的事情.

Notice that \(.*\)status=[^/]* would match up through survstatus=new in your example. That is probably not what you want? There doesn't seem to be a status= followed by a slash anywhere -- you really should explain in more detail what you are actually trying to accomplish.

您的问题标题是匹配后的所有行"，所以也许您想要text= 之后的所有内容?那么就是

Your question title says "all line after a match" so perhaps you want everything after text=? Then that's simply

sed 's/.*text=//'

即将 text= 替换为空，保留其余部分.(我相信你可以弄清楚如何将周围的脚本更改为 zcat file* | sed '/pattern/s/.*text=//' ... 哎呀，也许我的信任失败了.)

i.e. replace up through text= with nothing, and keep the rest. (I trust you can figure out how to change the surrounding script into zcat file* | sed '/pattern/s/.*text=//' ... oops, maybe my trust failed.)

这篇关于Sed:匹配后打印所有行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！