除了前面没有反斜杠的双引号外，匹配任何东西的正则表达式是什么? [英] What's the regex to match anything except a double quote not preceded by a backslash?

问题描述

换句话说，我有一个字符串:

In other words, I have a string like:

任何东西，转义双引号:\"，是的"这里的任何东西都不能匹配.

"anything, escaped double-quotes: \", yep" anything here NOT to be matched.

如何匹配引号内的所有内容?

How do I match everything inside the quotes?

我在想

^"((?<!\\)[^"]+)"

但是我的头在旋转，这应该是积极的还是消极的回顾?还是根本没用?

But my head spins, should that be a positive or a negative lookbehind? Or does it work at all?

如何匹配除双引号之外的任何字符，但前面没有反斜杠?

How do I match any characters except a double-quote NOT preceded by a backslash?

推荐答案

无需回看:

"([^"]|\\")*"

所以:匹配引号，并在其中:除了引号 ([^"]) 或 转义的引号 (\\")，任意多次(*).

So: match quotes, and inside them: every character except a quote ([^"]) or an escaped quote (\\"), arbitrarily many times (*).

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