重新编译中的Python正则表达式模式最大长度? [英] Python regex pattern max length in re.compile?
问题描述
我尝试在 Python 3 中使用 re.compile
编译一个大模式.
我尝试编译的模式由 500 个小词组成(我想从文本中删除它们).问题是它在大约 18 个单词后停止模式
Python 不会引发任何错误.
我要做的是:
stoplist = map(lambda s: "\\b" + s + "\\b", stoplist)stopstring = '|'.join(停止列表)stopword_pattern = re.compile(stopstring)
停止字符串没问题(所有单词都在),但模式要短得多.它甚至停在一个词的中间!
正则表达式模式有最大长度吗?
考虑这个例子:
导入重新stop_list = map(lambda s: "\\b" + str(s) + "\\b", range(1000, 2000))stopstring = "|".join(stop_list)stopword_pattern = re.compile(stopstring)
如果您尝试打印图案,您会看到类似
<预><代码>>>>打印(stopword_pattern)re.compile('\\b1000\\b|\\b1001\\b|\\b1002\\b|\\b1003\\b|\\b1004\\b|\\b1005\\b|\\b1006\\b|\\b1007\\b|\\b1008\\b|\\b1009\\b|\\b1010\\b|\\b1011\\b|\\b1012\\b|\\b1013\\b|\\b1014\\b|\\b1015\\b|\\b1016\\b|\\b1017\\b|\)这似乎表明该模式不完整.然而,这似乎是 __repr__
和/或 __str__
方法对 re.compile
对象的限制.如果您尝试对模式的缺失"部分执行匹配,您会看到它仍然成功:
I try to compile a big pattern with re.compile
in Python 3.
The pattern I try to compile is composed of 500 small words (I want to remove them from a text). The problem is that it stops the pattern after about 18 words
Python doesn't raise any error.
What I do is:
stoplist = map(lambda s: "\\b" + s + "\\b", stoplist)
stopstring = '|'.join(stoplist)
stopword_pattern = re.compile(stopstring)
The stopstring is ok (all the words are in) but the pattern is much shorter. It even stops in the middle of a word!
Is there a max length for the regex pattern?
Consider this example:
import re
stop_list = map(lambda s: "\\b" + str(s) + "\\b", range(1000, 2000))
stopstring = "|".join(stop_list)
stopword_pattern = re.compile(stopstring)
If you try to print the pattern, you'll see something like
>>> print(stopword_pattern)
re.compile('\\b1000\\b|\\b1001\\b|\\b1002\\b|\\b1003\\b|\\b1004\\b|\\b1005\\b|\\b1006\\b|\\b1007\\b|\\b1008\\b|\\b1009\\b|\\b1010\\b|\\b1011\\b|\\b1012\\b|\\b1013\\b|\\b1014\\b|\\b1015\\b|\\b1016\\b|\\b1017\\b|\)
which seems to indicate that the pattern is incomplete. However, this just seems to be a limitation of the __repr__
and/or __str__
methods for re.compile
objects. If you try to perform a match against the "missing" part of the pattern, you'll see that it still succeeds:
>>> stopword_pattern.match("1999")
<_sre.SRE_Match object; span=(0,4), match='1999')
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