Visual Studio、查找和替换、正则表达式 [英] Visual Studio, Find and replace, regex

问题描述

我正在尝试使用 Visual Studio 2005 中的查找和替换功能将所有 #include "whatever.h" 替换为 #include <whatever.h>.我使用正则表达式 \#include \"[az\.h]+\" 来查找包含语句.但我想知道如何构建替换正则表达式.

I am trying to replace all the #include "whatever.h" with #include <whatever.h> using find and replace functionality in Visual Studio 2005. I used the regex \#include \"[a-z\.h]+\" to find the include statement. But I am wondering how frame the replace regex.

\#include \<[a-z\.h]+\> 不起作用，也不会；它将语句 #include "whatever.h" 替换为 #include <[a-z.h]+>.我应该如何构建替换正则表达式以保留 whatever.h 原样?

\#include \<[a-z\.h]+\> did not work and won't; it replaces the statement #include "whatever.h" with #include <[a-z.h]+>. How shall I frame the replace regex to retain whatever.h as it is?

推荐答案

对于 before Visual Studio 2012 的版本:
当我这样做时它有效:
find include "{[a-zA-Z]+\.h}",
替换为 include <\1>.
与您的问题最相关的部分是花括号 {} 和反向引用 \1: \n 对第 n 组的引用由搜索表达式中的花括号表示.

For versions before Visual studio 2012:
It works when I do this:
find include "{[a-zA-Z]+\.h}",
replace with include <\1>.
The most relevant parts for your question are the curly braces {} and the back reference \1: \n references to the n'th group indicated by curly braces in the search expression.

对于版本 Visual Studio 2012 &向上:
从 VS2012 开始使用 .NET Framework 正则表达式.所以它应该是:
find include "([a-zA-Z]+\.h)",
替换为 include <$1>.

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