使用正则表达式匹配到某个模式 [英] match until a certain pattern using regex

问题描述

我在一个包含一些文本的文本文件中有字符串，如下所示:

I have string in a text file containing some text as follows:

txt = "java.awt.GridBagLayout.layoutContainer"

我希望获得类名之前的所有内容，"GridBagLayout".

I am looking to get everything before the Class Name, "GridBagLayout".

我尝试了以下内容，但我不知道如何摆脱 "."

I have tried something the following , but I can't figure out how to get rid of the "."

txt = re.findall(r'java\S?[^A-Z]*', txt)

我得到以下信息:"java.awt."

而不是我想要的:"java.awt"

关于我如何解决这个问题的任何指示?

Any pointers as to how I could fix this?

推荐答案

不使用捕获组，您可以使用前瞻((?= ... ) 业务).

Without using capture groups, you can use lookahead (the (?= ... ) business).

java\s?[^A-Z]*(?=\.[A-Z]) 应该可以捕获您想要的所有内容.分解如下:

java\s?[^A-Z]*(?=\.[A-Z]) should capture everything you're after. Here it is broken down:

java            //Literal word "java"
\s?             //Match for an optional space character. (can change to \s* if there can be multiple)
[^A-Z]*         //Any number of non-capital-letter characters
(?=\.[A-Z])     //Look ahead for (but don't add to selection) a literal period and a capital letter.

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