如何找到共同的元素只有在jQuery的2阵列之间 [英] How to find common elements only between 2 arrays in jquery
问题描述
变种ARRAY1 = [1,2,3,4,5,6]。
变种数组2 = [1,2,3,4,5,6,7,8,9];
我有两个数组像上面。现在我想用jQuery做以下的MVC 4。
-
如果两个数组的元素每次都相等,则显示消息/警报。例如所有的记录已经存在。
-
如果两个数组元素的每一个都不同则只需添加他们都在一个VAR,例如
VAR的ResultSet = ....
(其中7,8,9将存储) -
如果两个数组之间的共同然后为共同的元素一些因素显示一条消息,以元素,例如记录1,2,3,4,5,6已经存在,并在VAR添加不同的元素,例如
VAR的ResultSet = ....
(其中7,8,9将存储)。无论是消息和差异性的元素集合将在同一时间进行。
试试这个:
块引用>变种ARRAY1 = [1,2,3,4,5,6]中
数组2 = [1,2,3,4,5,6,7,8,9];VAR共同= $ .grep(数组1,函数(元素){
返回$ .inArray(元素,数组2)== -1!;
});的console.log(共同); //返回[1,2,3,4,5,6]。VAR ARRAY3 = array2.filter(函数(OBJ){返回array1.indexOf(OBJ)== -1;});//返回[7,8,9]。var array1 = [1, 2, 3, 4, 5, 6]; var array2 = [1, 2, 3, 4, 5, 6, 7, 8, 9];
I have two arrays like above. Now I want to do the following in MVC 4 with jQuery.
If every elements of both arrays are equal then show a message/alert. e.g. "All records already existing."
If every elements of both the arrays are different then just add them all in a "VAR", e.g.
var resultset = ....
(where 7,8,9 will stored)If few elements common between two arrays then for the common elements show a message with element, e.g. "Record 1,2,3,4,5,6 are already exists" and add the different elements in "VAR", e.g.
var resultset = ....
(where 7,8,9 will stored). Both the message and difference elements collection will perform at the same time.
解决方案Try this:
var array1 = [1, 2, 3, 4, 5, 6], array2 = [1, 2, 3, 4, 5, 6, 7, 8, 9]; var common = $.grep(array1, function(element) { return $.inArray(element, array2 ) !== -1; }); console.log(common); // returns [1, 2, 3, 4, 5, 6]; var array3 = array2.filter(function(obj) { return array1.indexOf(obj) == -1; }); // returns [7,8,9];
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