匹配电话号码的正则表达式 [英] Regular Expression for matching a phone number

问题描述

我需要一个正则表达式来匹配电话号码.我只想知道该号码是否可能是电话号码，并且可以是任何电话格式，美国或国际.所以我制定了一个策略来确定它是否匹配.

I need a regular expression to match phone numbers. I just want to know if the number is probably a phone number and it could be any phone format, US or international. So I developed a strategy to determine if it matches.

我希望它接受以下字符:0-9 以及 ,.()- 并可选择以 + 开头(对于国际号码).如果字符串有任何其他字符，则该字符串不应匹配.

I want it to accept the following characters: 0-9 as well as ,.()- and optionally start with a + (for international numbers). The string should not match if it has any other characters.

我试过了:

/\+?[0-9\/\.\(\)\-]/

但它匹配号码中间带有 + 的电话号码.它匹配包含字母字符的数字(我不想要).

But it matches phone numbers that have + in the middle of the number. And it matches numbers that contain alpha chars (I don't want that).

最后，我想将最小长度设置为 9 个字符.

Lastly, I want to set the minimum length to 9 characters.

有什么想法吗?

感谢您的帮助，我显然对 RegEx 的内容不太熟悉 :)

Thanks for any help, I'm obviously not too swift on RegEx stuff :)

推荐答案

嗯，你已经很接近了.试试这个:

Well, you're pretty close. Try this:

^\+?[0-9\/.()-]{9,}$

没有开始和结束锚点，您允许部分匹配，因此它可以匹配字符串 :-)+123 中的 +123.

Without the start and end anchors you allow partial matching, so it can match +123 from the string :-)+123.

如果您想要最少 9 个数字，而不是任何字符(因此 ---.../// 无效)，您可以使用:

If you want a minimum of 9 digits, rather than any characters (so ---.../// isn't valid), you can use:

^\+?[\/.()-]*([0-9][\/.()-]*){9,}$

或者，使用前瞻 - 在匹配 [0-9/.()-]* 的字符串之前，正则表达式引擎正在寻找 (\D*\d){9}，它是一个 9 位数字，每个数字前面可能有其他字符(我们稍后会验证).

or, using a lookahead - before matching the string for [0-9/.()-]* the regex engine is looking for (\D*\d){9}, which is a of 9 digits, each digit possibly preceded by other characters (which we will validate later).

^\+?(?=(\D*\d){9})[0-9\/.()-]*$

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