如何在 Ruby 中匹配完整的单词而不是子字符串 [英] How to match full words and not substrings in Ruby

问题描述

这是我的代码

stopwordlist = "a|an|all"
File.open('0_9.txt').each do |line|
line.downcase!
line.gsub!( /\b#{stopwordlist}\b/,'')
File.open('0_9_2.txt', 'w') { |f| f.write(line) }
end

我想删除单词 - a、an 和所有但是，它也匹配子字符串并删除它们

I wanted to remove words - a,an and all But, instead it matches substrings also and removes them

例如输入 -

Bromwell High is a cartoon comedy. It ran at the same time as some other programs about school life

我得到输出 -

bromwell high is  cartoon comedy. it r t the same time s some other programs bout school life

如你所见，它匹配了子字符串.

As you can see, it matched the substring.

如何让它只匹配单词而不匹配子字符串?

How do I make it just match the word and not substrings ?

推荐答案

正则表达式中的 | 运算符采用了尽可能广泛的范围.您的原始正则表达式匹配 \ba 或 an 或 all\b.

The | operator in regex takes the widest scope possible. Your original regex matches either \ba or an or all\b.

将整个正则表达式更改为:

Change the whole regex to:

/\b(?:#{stopwordlist})\b/

或将 stopwordlist 改为正则表达式而不是字符串.

or change stopwordlist into a regex instead of a string.

stopwordlist = /a|an|all/

更好的是，您可能想要使用 Regexp.union.

Even better, you may want to use Regexp.union.

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