正则表达式上的Python拆分字符串 [英] Python split string on regex

问题描述

我正在尝试使用正则表达式拆分字符串.

Frid​​ay 1Friday 11 JAN 11

我想要实现的输出是

['Friday 1', 'Friday 11', 'JAN 11']

到目前为止，我的代码片段没有产生预期的结果:

<预><代码>>>>进口重新>>>p = re.compile(r'(Sunday|Monday|Tuesday|Wednesday|Thursday|Friday|Saturday)\s*\d{1,2}')>>>filter(None, p.split('Friday 1Friday 11 Jan 11'))['星期五'、'星期五'、'1 月 11 日']

我的正则表达式有什么问题?

解决方案

问题在于捕获括号.此语法: (?:...) 使它们无法捕获.试试:

p = re.compile(r'((?:Friday|Saturday)\s*\d{1,2})')

I'm trying to split a string using a regular expression.

Friday 1Friday 11 JAN 11

The output I want to achieve is

['Friday 1', 'Friday 11', ' JAN 11']

My snippet so far is not producing the desired results:

>>> import re
>>> p = re.compile(r'(Sunday|Monday|Tuesday|Wednesday|Thursday|Friday|Saturday)\s*\d{1,2}')
>>> filter(None, p.split('Friday 1Friday 11 JAN 11'))
['Friday', 'Friday', ' JAN 11']

What am I doing wrong with my regex?

解决方案

The problem is the capturing parentheses. This syntax: (?:...) makes them non-capturing. Try:

p = re.compile(r'((?:Friday|Saturday)\s*\d{1,2})')

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