将字符串转换为正则表达式 ruby [英] Convert a string to regular expression ruby

问题描述

我需要将像 "/[\w\s]+/" 这样的字符串转换为正则表达式.

I need to convert string like "/[\w\s]+/" to regular expression.

"/[\w\s]+/" => /[\w\s]+/

我尝试使用不同的 Regexp 方法，例如:

I tried using different Regexp methods like:

Regexp.new("/[\w\s]+/") =>//\/[w ]+\//，类似Regexp.compile 和Regexp.escape.但是他们都没有像我预期的那样返回.

Regexp.new("/[\w\s]+/") => /\/[w ]+\//, similarly Regexp.compile and Regexp.escape. But none of them returns as I expected.

此外，我还尝试删除反斜杠:

Further more I tried removing backslashes:

Regexp.new("[\w\s]+") =>/[w ]+/ 但运气不好.

然后我试着做的很简单:

Then I tried to do it simple:

str = "[\w\s]+"
=> "[w ]+"

它逃脱了.现在字符串如何保持原样并转换为正则表达式对象?

It escapes. Now how could string remains as it is and convert to a regexp object?

推荐答案

看起来这里你需要将初始字符串放在单引号中(参考 本页)

Looks like here you need the initial string to be in single quotes (refer this page)

>> str = '[\w\s]+'
 => "[\\w\\s]+" 
>> Regexp.new str
 => /[\w\s]+/ 

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