如何在这个“密码复杂性"正则表达式中允许下划线 [英] How to allow underscore in this 'Password Complexity' regex

问题描述

这是:

/(?=^.{8,}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$/

它仅在密码包含大写和小写字母以及 1 位数字或 1 个特殊字符时才通过，但是我希望下划线 _ 也算作特殊字符，目前还没有，如何修改正则表达式，以便它允许下划线算作特殊字符?

It only passes if the password contains upper case AND lower case letters, and also either 1 digit or 1 special character, however I want underscore _ to count as a special character as well and it currently does not, how can modify this regex so that it will allow underscore to count as a special character?

这里是上下文...

jQuery.validator.addMethod("complexity", function(value, element) {
    return this.optional(element) || /(?=^.{8,}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$/.test(value);
}, "password is not complex, see requirements above");

推荐答案

/(?=^.{8,}$)((?=.*\d)|(?=.*[\W_]+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$/

aioobe 将 \W 替换为 [\W_]

aioobe was close replace \W with [\W_]

只是让您知道这将空格视为特殊字符.

Just so you know this considers a space a special character.

此外，我没有看到您在哪里检查数字.没关系我找到了.(复杂的正则表达式就像一个 wheres waldo.)

Also I don't see where you are checking for numbers. nevermind I found it. (man complex regexes are like a wheres waldo.)

这是一个不允许空格的简化版本(并且更容易维护)

Here is a simplifed version that does not allow spaces (and it is easyier to maintain)

(?=^.{8,}$)(?=.*[a-z])(?=.*[A-Z])(?=.*[\W_])(?=^.*[^\s].*$).*$
^          ^          ^          ^            ^
|          |          |          |            L--does not contain a whitespace
|          |          |          L--at least one non word character(a-zA-Z0-9_) or _ or 0-9
|          |          L--at least one upper case letter
|          L--at least one lowercase Letter
L--Number of charaters

这些是你的积木

(?=.*[a-z]) // Whatever is inside the [] meens the string contains at least one charter inside that set.
            // If you wanted a minimum of three lowercase letters you can chain the inner block like so 
               (?=(.*[a-z]){3,})

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