正则表达式，xsd 中的模式匹配 [英] Regular Expression, pattern matching in xsd

问题描述

我想知道如何为除 * 和 + 之外的任何字符制作正则表达式.我试过 ([^*+]) 和 (\[^*+]) 但两个表达式似乎都不正确.有人可以指出我正确的方向吗?谢谢.

I was wondering how to make a regular expression for any character except * and + . I've tried ([^*+]) and (\[^*+]) but both expressions seem to be incorrect. Can someone please point me in the right direction? Thanks.

这是一个代码片段.我已将下面建议的 reg ex 附加到 Visual Studio 中，当我输入常规字符串时，它仍然会生成错误.

Here is a code snipet. I've attached the reg ex suggested below into visual studio and it still generates an error when i enter in a regular string.

<xsd:element name="elementName">
    <xsd:simpleType>
        <xsd:restriction base="xsd:string">
            <xsd:pattern value="/^[^*+]+$/"></xsd:pattern>
        </xsd:restriction>
    </xsd:simpleType>
</xsd:element>   

我使用的示例字符串是test"结果是模式约束失败，当前正则表达式:/^[^*+]+$/

The example string I'm using is "test" The result is pattern constraint fail with the current reg ex: /^[^*+]+$/

推荐答案

在 XML Schema regex flavor 中，您不得添加正则表达式分隔符(即 /^[^*+]+$/ 两端的 /).您也不需要使用锚点(即开头的 ^ 和结尾的 $)；所有正则表达式匹配都会自动锚定在两端.该行应为:

In the XML Schema regex flavor, you must not add regex delimiters (i.e., the / at either end of /^[^*+]+$/). You also don't need to use anchors (i.e., the ^ at the beginning and $ at the end); all regex matches are automatically anchored at both ends. That line should read:

<xsd:pattern value="[^*+]+"></xsd:pattern>

...意味着整个元素必须由一个或多个除了 * 和 + 之外的任何字符组成.

...meaning the whole element must consist of one or more of any characters except * and +.

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