使用正则表达式排除字符串 [英] Excluding strings using regex

问题描述

我正在创建一个正则表达式，其中包含除时间"、小时"、分钟"之外的所有模式所以，解决了这个问题:

I was working on creating a regex which will include all patterns except 'time', 'hour', 'minute' so, worked this out:

^(?:(?!time).)*$

我如何为其他两个词添加?我试过如下，但不正确.

how do i add for the other 2 words also? I tried as follows but it is incorrect.

^(?:(?![time][hour][minute]).)*$

有没有更好的方法来做到这一点?

Is there a better way to do this?

我没有添加可以接受的值，因为它的范围从数字到字母再到符号等.

I am not adding the values which can be accepted as it ranges from numbers to alphabets to symbols etc.

请帮忙.

谢谢

推荐答案

^(?:(?!time|hour|minute).)*$

| 是交替.这意味着在字符串中的所有点，我们都不会查看任何这些表达式(时间、小时或分钟).[] 是错误的，因为它创建了一个字符类.

| is alternation. This means that at all points in the string, we are not looking at any of those expressions (time, hour, or minute). [] is wrong because that creates a character class.

所以这意味着，不看(a t、i、m 或 e)，然后(a h、o、u 或 r)等.

So it means, not looking at (a t, i, m, or e), then (a h, o, u, or r), etc.

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