如何使用 JavaScript 替换字符串中除第一个和最后一个字符之外的所有字符 [英] How to replace all characters in a string except first and last characters, using JavaScript

问题描述

我需要用 JavaScript 编写一个解决方案，用 * 替换字符串中的所有字符，但第一个和最后一个字符除外.我对 RegEx 不是很熟悉，但试图使用以下方法来实现解决方案:

I need to write a solution in JavaScript to replace all the characters in a string with a *, except for the first and last characters. I'm not very familiar with RegEx but was trying to use the following to achieve the solution:

var regex = /\.(?=^)(?!=$)/;
    const censored = w.replace(regex)
    console.log(censored)

关于如何实现这一目标的任何想法?

Any ideas on how I can achieve this?

推荐答案

使用lookaheads的想法是可行的，让我们纠正几个错误:

The idea of using lookaheads is viable, let's correct a few mistakes:

var regex = /(?<!^).(?!$)/g;
var w = 'fork'
var censored = w.replace(regex, '*')

console.log(censored)

但是请注意，后视(?<= 和 ?<!)来自 ES 2018，尚未得到普遍支持.(正如在另一个答案中指出的那样，您实际上不需要在这里进行后视，前瞻 (?!^) 也可以).还是...

Do note, however, that lookbehinds (?<= and ?<!) are from ES 2018 and not universally supported yet. (As pointed out in another answer, you actually don't need a lookbehind here, a lookahead (?!^) would do as well). Stil...

您也可以砍掉第一个字符并替换其余字符:

You can also chop off the first char and replace the rest:

var w = 'fork'
var censored = w[0] + w.slice(1).replace(/.(?!$)/g, '*')

console.log(censored)

最后，这里有一种完全不需要任何正则表达式的方法:

Finally, here's a way to do that without any regexes at all:

var w = 'fork'
var censored = w[0] + '*'.repeat(w.length - 2) + w.slice(-1)

console.log(censored)

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