仅当前面或后面没有数字时才匹配 [英] Match only if not preceded or followed by a digit

问题描述

我用这个正则表达式在代码库中查找电话号码:

I have this regular expression to look for phone numbers in a codebase:

\\d{3}[\.\s-]?\d{3}[\.\s-]?\d{4}\g

如何修改它，使其不会匹配数字前面或后面是数字的实例?

How can I modify this so that it will not match instances where the number is preceded or followed by a digit?

18005555555 (should not match)
80055555551 (should not match)
"8005555555" (should match)
s800-555-5555 (should match)
8005555555 (should match)
800.555.5555 (should match)

编辑:我不是要匹配整个单词"，因为匹配前后有一个空格是不够的.请参阅上面的第三个示例，该示例也应该返回匹配项.

Edit: I'm not trying to "match the whole word", because it is not sufficient that the match is preceded by and followed by a space. See the 3rd example of above that should also return a match.

我只想匹配前面或后面没有数字的匹配项.

I want to match only instances where the match is not preceded or followed by a digit.

换句话说:

[NOT DIGIT][PHONE NUMBER][NOT DIGIT]

推荐答案

Lookahead 和 Lookbehind 将帮助您解决这些限制 - 如果它们受支持，例如

Lookahead and lookbehind will help you with these restrictions - if they are supported, like

/(?<!\d)\d{3}[.\s-]?\d{3}[.\s-]?\d{4}(?!\d)/g

如果不支持，您可以用 (?:^|\D) 替换后视 (?<!\d).如果不支持，您可以将前瞻 (?!\d) 替换为 (?:\D|$).

You can replace the lookbehind (?<!\d) with (?:^|\D) if it is not supported. You can replace the lookahead (?!\d) with (?:\D|$) if it is not supported.

您可以在此处找到演示:https://regex101.com/r/aS8jQ8/1

You can find a demo here: https://regex101.com/r/aS8jQ8/1

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