从python中的字符串中提取年份 [英] Extracting year from string in python

问题描述

我如何解析 foll.在python中提取年份:

How can I parse the foll. in python to extract the year:

'years since 1250-01-01 0:0:0'

答案应该是 1250

推荐答案

有很多种方法可以做到，这里有几个选项:

There are all sorts of ways to do it, here are several options:

• dateutil 解析器在模糊" 模式:

• dateutil parser in a "fuzzy" mode:

In [1]: s = 'years since 1250-01-01 0:0:0'

In [2]: from dateutil.parser import parse

In [3]: parse(s, fuzzy=True).year  # resulting year would be an integer
Out[3]: 1250

带有捕获组的正则表达式:

In [2]: import re

In [3]: re.search(r"years since (\d{4})", s).group(1)
Out[3]: '1250'

先用since"再用破折号分割:

splitting by "since" and then by a dash:

In [2]: s.split("since", 1)[1].split("-", 1)[0].strip()
Out[2]: '1250'

或者甚至可能被第一个破折号分割并切片第一个子字符串:

or may be even splitting by the first dash and slicing the first substring:

In [2]: s.split("-", 1)[0][-4:]
Out[2]: '1250'

最后两个涉及更多的移动部分"，可能不适用，具体取决于输入字符串的可能变化.

The last two involve more "moving parts" and might not be applicable depending on possible variations of the input string.

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