正则表达式不会在第一个空格处停止 [英] Regex not stopping at first space

问题描述

尝试创建一个匹配左括号的模式，并获取它和它遇到的下一个空间之间的所有内容.我认为 \[.*\s 会实现这一点，但它从第一个左括号开始就获得了所有内容.我怎么能告诉它在下一个空间中断?

Trying to create a pattern that matches an opening bracket and gets everything between it and the next space it encounters. I thought \[.*\s would achieve that, but it gets everything from the first opening bracket on. How can I tell it to break at the next space?

推荐答案

\[[^\s]*\s

.* 是贪婪的，会吃掉所有东西，包括空格，直到最后一个空格字符.如果您将其替换为 \S* 或 [^\s]*，它将仅匹配除空格之外的零个或多个字符块.

The .* is a greedy, and will eat everything, including spaces, until the last whitespace character. If you replace it with \S* or [^\s]*, it will match only a chunk of zero or more characters other than whitespace.

可能需要屏蔽左括号.如果你用 ^\s 否定 \s，表达式应该吃除空格之外的所有东西，然后是一个空格，这意味着直到第一个空格.

Masking the opening bracket might be needed. If you negate the \s with ^\s, the expression should eat everything except spaces, and then a space, which means up to the first space.

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