如何将一个字符串与另一个之间有空格的字符串进行比较 [英] How to compare a string with another where the one has space in between

问题描述

我如何比较这两个字符串:

How do I compare these two string :

val a = "fit bit versa"
val b = "fitbit"

另一个例子

val a = "go pro hero 6"
val b = "gopro"

另一个例子

val a = "hero go pro  6"
val b = "gopro"

另一个例子

val a = "hero 6 go pro"
val b = "gopro"

我想为上述比较获得真实"但不是在这里:

I want to get "true" for the above comparisons but not here:

val a = "vegan protein powder"
val b = "vega"

这应该是假的.

目前我在做:

def matchPattern(a:String, b: String):String=
{
      val dd = a.split(" ")
      val result = dd.map(_.toLowerCase())
      if(result contains b.toLowerCase) true 
      else false
}

这适用于最后一种情况，但不适用于其他情况.

This works for last case but not the rest.

有什么建议吗?

推荐答案

这是一种使用 sliding(i) 的方法，其中 i 的范围从 2 到 word-count ina，组装所有可能连接的相邻单词的列表.然后检查 b 是否与列表中的任何元素完全匹配，如下所示:

Here's one approach using sliding(i), where i ranges from 2 to word-count in a, to assemble a list of all possible concatenated adjacent words. It is then checked to see whether b exactly matches any of the elements in the list, as shown below:

def matchPattern(a: String, b: String): Boolean = {
  val words = a.toLowerCase.split("\\s+")

  val concats = (2 to words.size).foldLeft(words)(
    (acc, i) => acc ++ words.sliding(i).map(_.mkString)
  )

  concats contains b.toLowerCase
}

matchPattern("Hero go Pro 6", "gopro")
// res1: Boolean = true

matchPattern("Hero go Pro 6", "gopro6")
// res2: Boolean = true

matchPattern("Vegan protein powder", "vega")
// res3: Boolean = false

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