匹配括号内的所有子字符串，但那些以列入黑名单的单词开头 [英] Matching all substrings inside parentheses but those starting with blacklisted word

问题描述

在 PHP 中，使用 preg_replace，如何编写正则表达式，以便括号中的除The"之外的任何短语 &前面有空格被删除.例如，

In PHP, using preg_replace, how do I write a regular expression so that any phrase, except "The," in parenthesis & preceded by a space is deleted. E.g.,

Concordia University (Anything But The) => Concordia University
American University (The) => American University (The)

推荐答案

preg_replace 是否支持否定前瞻?如果是这样，你可以做这样的事情......

Does preg_replace support negative lookaheads? If so you can do something like this...

\((?!The\)).*?\)

这篇关于匹配括号内的所有子字符串，但那些以列入黑名单的单词开头的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！