字母表、下划线、连字符、撇号的正则表达式 [英] Regular expression for alpahbet,underscore,hyphen,apostrophe only

问题描述

我想要一个只接受字母、连字符、撇号、下划线的正则表达式.我试过了

I want a regular expression that accept only alphabets,hyphen,apostrophe,underscore. I tried

/^[ A-Za-z-_']*$/

但它不起作用.请帮忙.

but its not working. Please help.

推荐答案

您的正则表达式错误.试试这个:

Your regex is wrong. Try this:

/^[0-9A-Za-z_@'-]+$/

或

/^[\w@'-]+$/

连字符需要在字符类中的第一个或最后一个位置以避免转义.此外，如果不允许空字符串，则使用 +(1 或更多)代替 *(0 或更多)

Hyphen needs to be at first or last position inside a character class to avoid escaping. Also if empty string isn't allowed then use + (1 or more) instead of * (0 or more)

说明:

^ assert position at start of the string
[\w@'-]+ match a single character present in the list below
Quantifier: Between one and unlimited times, as many times as possible
\w match any word character [a-zA-Z0-9_]
@'- a single character in the list @'- literally
$ assert position at end of the string

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