正则表达式在字符串中查找 Youtube 链接 [英] Regex to find Youtube Link in string

问题描述

我有一个这样的字符串:

I have a string like that:

Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard  dummy text ever since the 1500s, https://www.youtube.com/watch?v=7TL02DA5MZM when an unknown printer took a galley of type and scrambled it to make a type

这就是我所拥有的:

preg_match("(?:http://)?(?:www.)?(?:youtube.com|youtu.be)/(?:watch\?)?([^\s]+?)", $content, $m);
    var_dump( $m );

并希望从中提取 youtube 链接.视频 ID 也可以.

and want to extract the youtube link form it. The video id, would be okay, too.

感谢您的帮助！

推荐答案

这对你有用，

\S*\bwww\.youtube\.com\S*

\S* 匹配零个或多个非空格字符.

\S* matches zero or more non-space characters.

代码是，

preg_match('~\S*\bwww\.youtube\.com\S*~', $str, $matches);

演示

我对你原来的正则表达式做了一些更正.

And i made Some corrections to your original regex.

(?:https?://)?(?:www.)?(?:youtube.com|youtu.be)/(?:watch\?v=)?([^\s]+)

演示

$str = "Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard  dummy text ever since the 1500s, https://www.youtube.com/watch?v=7TL02DA5MZM when an unknown printer took a galley of type and scrambled it to make a type";
preg_match('~(?:https?://)?(?:www.)?(?:youtube.com|youtu.be)/(?:watch\?v=)?([^\s]+)~', $str, $match);
print_r($match);

输出:

Array
(
    [0] => https://www.youtube.com/watch?v=7TL02DA5MZM
    [1] => 7TL02DA5MZM
)

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