Python正则表达式替换为ASCII值 [英] Python regex replace with ASCII value

问题描述

我的输入字符串类似于He#108##108#o，输出应该是Hello.

My input string is something like He#108##108#o and the output should be Hello.

基本上我想用##中数字的相关ASCII字符替换每个#[0-9]+#.

Basically I want to replace each #[0-9]+# with the relevant ASCII characters of the number inside the ##.

推荐答案

在正则表达式中使用替换函数，提取数字，将它们转换为整数，然后转换为字符:

Use a replacement function in your regex, which extracts the digits, converts them to integer, and then to character:

import re

s = "He#108##108#o"

print(re.sub("#(\d+)#", lambda x : chr(int(x.group(1))), s))

结果:

Hello

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